Answer: ok so for 5 and 125 it is 65 and 25
for 1 and 9 it is 5 and 3 and for 4 and 9 it is 13/2 and 6
Let two number A and B, and A >B
as we know A+10=2B① && A+B =38②
①-② solve that
B=16 so A=22
so, they are 16 and 22
Answer:
x=10
Step-by-step explanation:
We can use the angle bisector theorem to solve this problem
8 12
-------- = ---------
x+4 2x+1
Using cross products
8(2x+1) = 12(x+4)
Distribute
16x+8 = 12x+48
Subtract 12x from each side
16x -12x +8 = 12x-12x +48
4x +8 = 48
Subtract 8 from each side
4x+8-8 = 48-8
4x = 40
4x/4 = 40/4
x=10