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IgorLugansk [536]
2 years ago
11

Which graph represents the function f(x)=4⋅3x ? Please help!!!

Mathematics
1 answer:
S_A_V [24]2 years ago
6 0

Answer:

Option D is correct.

Step-by-step explanation:

An exponential function is in the form of y =ab^x where a is the initial value and b≠ 0 , b >1 .

Given: The function f(x) = y = 4 \cdot 3^x           ......[1]

The domain is all real numbers and the range is y > 0.

y-intercept defined as the graph crosses the y-axis.

Substitute the value of x= 0 in [1] to solve for y;

y = 4 \cdot 3^0  = 4

y-intercept = (0, 4)

End behavior:

when b =3 >1

then;

as x \rightarrow \infty , f(x)\rightarrow \infty

as  x \rightarrow -\infty , f(x)\rightarrow 0

therefore, the only graph which represents the function y = 4 \cdot 3^x   is Option D



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Which ordered pair makes both inequalities true?
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Answer:

The ordered pair which makes both the inequalities true is = (–2, 2)

Step-by-step explanation:

inequalities are the relationships between two expressions which are not equal to one another.

Inequalities are represented by the following relations:

  • ≤: "less than or equal to"
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an inequality is a relation which makes a non-equal comparison between two numbers or other mathematical expressions. It is used most often to compare two numbers on the number line by their size.

so, the option B(-2,2) satisfies  the inequalities expressions given in the question

therefore we can conclude that (-2,2) is the ordered pair which ,makes both the given inequalities true.

so the correct answer is (-2,2)

learn more about inequalities at

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To solve for y in the equations 2x + y = 5, subtract 2 from both sides of the equation true or false
antiseptic1488 [7]
Hey there!

Here is your answer:

<u>The proper answer to this question is option B "false". </u>

Reason:

<span><u><em>To solve for y in the equations 2x + y = 5, subtract 2 from both sides of the equation. This statement is false. In order to solve this you have to divide 2 on both sides.</em></u>

<em>Therefore the answer is option B.</em>

If you need anymore help feel free to ask me!

Hope this helps!

~Nonportrit
</span>
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