Using the critical point concept, it is found that a = -3 and b = 7.
<h3>What are the critical points of a function?</h3>
- The critical points of a function are the values of x for which:
In this problem, the function is:
Hence, the derivative is:
Then:
Since the critical point is at x = 2, we have that:
Then:
Critical point at (2,3) means that when 
, then:
You can learn more about the critical point concept at brainly.com/question/2256078
Answer:
the handle will end up on the left side
Step-by-step explanation:
The cup is rotated 180 degrees clockwise. Therefore, I assume the rotation is about the center of the bottom of the cup. Also, only the cup is rotated, not the saucer (although this makes no difference in this problem).
The result is that the handle will end up on the left side. The cup will still be right side up.
Answer:
The lower class boundary for the first class is 140.
Step-by-step explanation:
The variable of interest is the length of the fish from the North Atlantic. This variable is quantitative continuous.
These variables can assume an infinite number of values within its range of definition, so the data are classified in classes.
These classes are mutually exclusive, independent, exhaustive, the width of the classes should be the same.
The number of classes used is determined by the researcher, but it should not be too small or too large, and within the range of the variable. When you decide on the number of classes, you can determine their width by dividing the sample size by the number of classes. The next step after getting the class width is to determine the class intervals, starting with the least observation you add the calculated width to get each class-bound.
The interval opens with the lower class boundary and closes with the upper-class boundary.
In this example, the lower class boundary for the first class is 140.
Answer:
The three natural numbers whose sum and product are equal are 1, 2 and 3.
By eg.,1+2+3=6 &1×2×3=6.
Answer:
The equation of line Le is 5 y + x + 89 = 0
Step-by-step explanation:
Given as :
The line Li passes through point (1,2)
The slope of line Li (m) = 5
So, equation of line y = m x + c
or, 2 = 5 × 1 + c
Or, c = 2 - 5 = -3
∴ Eq of line Li is
y = 5 x - 3
Another line Le is perpendicular to line Li
Let the slope of line Le = M
The line Le meet at points where x = 4
So, for perpendicular property
Products of slopes = - 1
So, m × M = - 1
or, M = - 
Or. M = - 
Now equation of line Le is y = M x + c
∵ Line Le meet the line Li at x = 4
So, y = 5 × 4 - 3
I.e y = 20 - 3
Or, y = 17
Now, equation of line Le with slope - and passes through points ( 4 , 17 ) is
y = M x + c
or, 17 = - × 4 + c
or, 17 + 
= c
So, c = 
Or, c = - 
∴ Equation of line Le is y = - x -
ie. 5 y = - x - 89
or, 5 y + x + 89 = 0
Hence The equation of line Le is 5 y + x + 89 = 0 answer
