Part A: As we have learned when given a pair of equations, we must always find a Point of Intersection....or, in other words...the solution of the lines given to us. As we know there can be one solution, in this case we view the graph; see where they intersect, and realize that the solution to these lines (Point of Intersection) is at (4,4).
Thus, your answer.
Well let’s make it a decimal.
.75 = .84 + Y
So if .84 is more than .75 then subtract
.75 from .84 and you have your answer then convert to fraction
Play usually continues 7.Qf3+ Ke6 8.Nc3 (see diagram). Black will play 8...Nb4 or 8...Ne7 and follow up with c6, bolstering his pinned knight on d5. If Black plays 8...Nb4, White can force the b4 knight to abandon protection of the d5 knight with 9.a3?! Nxc2+ 10.Kd1 Nxa1 11.Nxd5, sacrificing a rook, but current analysis suggests that the alternatives 9.Qe4, 9.Bb3 and 9.O-O are stronger. White has a strong attack, but it has not been proven yet to be decisive.
Because defence is harder to play than attack in this variation when given short time limits, the Fried Liver is dangerous for Black in over-the-board play, if using a short time control. It is also especially effective against weaker players who may not be able to find the correct defences. Sometimes Black invites White to play the Fried Liver Attack in correspondence chess or in over-the-board games with longer time limits (or no time limit), as the relaxed pace affords Black a better opportunity to refute the White sacrifice.
Answer: The relation is a function.
Step-by-step explanation: Since there is one value of y for every value of x in (-2,4), (3,7), (0,8), (5,8), and (1,6), this relation is a function.
I hope this helps you out!
Answer:
13 gb have been downloaded.
Step-by-step explanation:
