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3 years ago

Solve for x: 2|x − 3| + 1 = 7 (5 points) x = 0, x = 6 x = −1, x = 6 x = 0, x = 9 No solutions

Mathematics

2 answers:

Dominik [7]3 years ago

8 0

2|x-3|+1=7
2|x-3|=6
|x-3|=3

x-3 = 3 or x-3 = -3
x=0 or 6

RSB [31]3 years ago

4 0

1. x>-2 distribute the three and get 3x+6>0 subtract the 6 to get 3x>-6 then divide by 2 to get -2.

2.x>6 distribute 8 to get 8x+8 and distribute 7 to get 7x+14. Subtract over the 8 to get 8x>7x+6 then subtract over 7x to get x>6

3.distribute the 9 and the 4 to get 9x-27<4x+40 add over the 27 and get 9x<4x+67 subtract over the 4x to get 5x<67 divide by 5 and get x<67/5

4. distribute the 3 and the 2 to get 3x+3 + 2x+4>0 add together the like terms 3x+2x=5x and 3+4=7 to get 5x+7>0 subtract over the seven to get 5x>-7 and then divide by 5 to get x>-7/5 5. first add over -7 to get -9x/11<2. after that multiply by 11 to get -9x<22 then divide by -9 (MAKE SURE YOU FLIP THE INEQUALITY SIGN WHEN MULTIPLYING OR DIVIDING BY A NEGATIVE LIKE -9 IN THIS CASE) you get x>-22/9 6. Add over the 5 to get 3x<9 divide by 3 and get x

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Below in bold.

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2 years ago

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Step-by-step explanation:

i) The best approach to estimate graphically the solution of $4\cdot x^{2} - 4\cdot x - 1 = 0$ is graphing the following system of equations:

$y = 4\cdot x^{2}-4\cdot x - 1$ (1)

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And labeling the points in which both intersects each other. We include the result in the image 'solution-i'. The approximate solutions are: $x_{1} \approx -0.207$ , $x_{2} \approx 1.207$ .

ii) The best approach to estimate graphically the solution of $4\cdot x^{2} - 4\cdot x - 1 = 2$ is graphing the following system of equations:

$y = 4\cdot x^{2}-4\cdot x - 1$ (1)

$y = 2$ (2)

And labeling the points in which both intersects each other. We include the result in the image 'solution-ii'. The approximate solutions are: $x_{1}\approx -0.5$ , $x_{2} \approx 1.5$ .

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3 years ago