1. x>-2 distribute the three and get 3x+6>0 subtract the 6 to get 3x>-6 then divide by 2 to get -2.
2.x>6 distribute 8 to get 8x+8 and distribute 7 to get 7x+14. Subtract over the 8 to get 8x>7x+6 then subtract over 7x to get x>6
3.distribute the 9 and the 4 to get 9x-27<4x+40 add over the 27 and get 9x<4x+67 subtract over the 4x to get 5x<67 divide by 5 and get x<67/5
4. distribute the 3 and the 2 to get 3x+3 + 2x+4>0 add together the like terms 3x+2x=5x and 3+4=7 to get 5x+7>0 subtract over the seven to get 5x>-7 and then divide by 5 to get x>-7/5 5. first add over -7 to get -9x/11<2. after that multiply by 11 to get -9x<22 then divide by -9 (MAKE SURE YOU FLIP THE INEQUALITY SIGN WHEN MULTIPLYING OR DIVIDING BY A NEGATIVE LIKE -9 IN THIS CASE) you get x>-22/9 6. Add over the 5 to get 3x<9 divide by 3 and get x
If you subtract 1.1 from 5.8 you will end up with 4.7 then you subtract 10^7 from 10^8 which will give you 10^1 then you add the seven back which will give you your answer of 4.7 10^8
Explanation: 1- getting the value of x: We are given that: side AB is congruent to side DF. This means that: AB = DF 3(2x+10) = 12x + 12 6x + 30 = 12x + 12 12x - 6x = 30 - 12 6x = 18 x = 18/6 x = 3
2- getting the value of y: We are given that: side BC is congruent to side FG. This means that: BC = FG 2y + 12 = 2(2y-3) 2y + 12 = 4y - 6 4y - 2y = 12 + 6 2y = 18 y = 18/2 y = 9