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natima [27]
3 years ago
15

Please help me this is due tommorow i need help with 21 through 24.

Mathematics
2 answers:
PilotLPTM [1.2K]3 years ago
7 0
21. 2 divided by 1/3= x

22. 1.75 divided by six = x

23. 16 divided by 1/4 =x

24. 28 divided by 1/48=x


Natasha_Volkova [10]3 years ago
4 0
21. 6 eggs
22. 10.5 feet
23. 64 inches
24. 1,344 inches long
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The jogging path at the park is 2.7 miles long. Miriam completed one lap of the path, walking part and jogging part. She hogs ha
Nimfa-mama [501]

Answer:

Miriam walks for 1.8 miles and jogs for 0.9 miles.

Step-by-step explanation:

The path for jogging is 2.7 miles.

One lap of the path, that is 2.7 miles, is completed by Miriam by jogging part and walking part.

Let the jogging part be x miles.

It is given she jogs half the distance she walks , therefore we can say that she walks for 2x miles.

So we can say that 2x + x  = 2.7 miles     ⇒    3x  = 2.7 miles

                                                                   ⇒   x  = 0.9 miles.

Therefore Miriam walks for 1.8 miles and jogs for 0.9 miles.

6 0
3 years ago
A man 50 years old has 8 sons born of equal intervals. The sum of the ages of the father and sons is 186. What is the age of the
Rudiy27
<span>let x be the interval, then: 186 = 50 + 3 + (3+x) + (3+2x) + (3+3x) + (3+4x) + (3+5x) + (3+6x) + (3+7x) 186 = 74 + 28x x = 4 Eldest son age = 3+7x = 3+28 = 31.</span>
8 0
4 years ago
Select all the correct answers.
evablogger [386]
Answer:
The 3rd and 4th option

Explanation:
A function only works when the input (x) only has one output (y).
The first, second, and the last option has the input has two or more outputs.

Fun Fact:
It is okay for the outputs to have more then in input, but not okay for the input to have more then one output.

I hope this help and have a nice day :)
6 0
3 years ago
6 hours more per week than Theodore studies
Flura [38]

Answer:

who is Theodore and what even is the question?

3 0
3 years ago
In an experiment to measure the lifetimes of parts manufactured from a certain aluminum alloy, 73 parts were loaded cyclically u
kari74 [83]

Answer:

0.0094.

Step-by-step explanation:

For the given experiment, let X be the lifetimes of parts manufactured from a certain aluminum alloy.

sample size =73

Sample mean = 784

Sample standard deviation = 120

Let µ represent the mean number of kilocycles to failure for parts of this type.

Null hypothesis, H0 : µ ≤ 750

Alternative hypothesis, H1 : µ > 750.

z=\dfrac{\overline{X}-\mu}{\frac{s}{\sqrt{n}}}

where,

\overline{X} is sample mean.

\mu is population mean.

s is sample standard deviation.

n is the sample size.

z=\dfrac{783-750}{\frac{120}{\sqrt{73}}}

z=2.35

It is a right tailed test because alternative hypothesis is µ > 750. So, P-value is the probability of observing a sample mean greater that 783 or the probability of P(z>2.35).

P=P(z>2.35)

P=1-P(z

P=1-0.9906

P=0.0094

Therefore the P-value is 0.0094.

5 0
3 years ago
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