Translation of question
A ship is used to measure the depth of the sea using sound devices. A sound was fired at the bottom of the water and five seconds later there was a bounce. If the speed of sound in the water is 1500 m / s, then the depth of the water is
Answer:
3750 m
Explanation:
For sound to bounch back and be heard, this phenomenon is echo. Therefore, the distance traveled is 2d. Considering that speed is distance per unit time, expressed as s=d/t where d is distance, t is time and s is speed, in this case we say s=2d/t. Making d the subject of the formula then d=0.5st
Given 5 s as time and 1500 m/s as speed, we deduce that d=0.5*1500*5=3750 m
As the room becomes warmer, the temperature of the thermistor will increase as well. The resistance of thermistors reduces when their temperature increases; thus, the current to the motor will increase and the fan will run faster when temperature is increased.
<span>Before you meet with a sexual assault victim, you run through the advocacy steps in your mind. The second step in advocacy process is to k</span><span>now your audience. It is multi-layered, from policy makers to media to key </span>constituencies<span> to public. Your research should consider whether it is provincial or health authorities or public.</span><span />
Answer: 8 years
Explanation:
According to Kepler’s Third Law of Planetary motion <em>“The square of the orbital period of a planet is proportional to the cube of the semi-major axis (size) of its orbit”:</em>
<em />
(1)
In other words: this law states a relation between the orbital period of a body (moon, planet, satellite, comet, asteroid) orbiting a greater body in space (the Sun, for example) with the size of its orbit.
However, if is measured in years (Earth years), and is measured in astronomical units (equivalent to the distance between the Sun and the Earth: ), equation (1) becomes:
(2)
This means that now both sides of the equation are equal.
Knowing and isolating from (2):
(3)
(4)
Finally:
This is the period of the asteroid
Answer:
The elastic potential energy of the spring is 0.28 J
Explanation:
Given;
mass of the block, m = 0.05 kg
spring constant, k = 350 N/m
extension of the spring, x = 4 cm = 0.04 m
The elastic potential energy of the spring is calculated as;
Therefore, the elastic potential energy of the spring is 0.28 J