Missing question (found on internet):
"what is the force of the car?"
Solution:
According to Newton's second law, the force of the car is equal to the product between its mass and its acceleration:

For the car in the problem,


So the force that accelerates the car is
The resistance of two things in series is the SUM of their individual resistances. So the resistance of two bulbs in series is <u><em>double</em></u> the resistance of one bulb.
(If they're in parallel, their combined resistance is <u><em>1/2</em></u> the resistance of one bulb.)
So two bulbs <em>in series</em> is the greater resistance. <em>(a) </em>
Answer:
decreasing the applied force and increasing the distance is the answer I hope it will help you please follow me
Answer:
b. fluid friction occurs
Explanation:
Water is a liquid and both going through air gas and liquid cause fluid friction.
Answer: 3.13 m
Explanation:
Given
mas of the ball is m=10 kg
The ball rolls down a vertical distance of 5 m
Spring constant of spring is 
Here, the potential energy of the ball converted into kinetic energy which in turn converts into elastic potential energy
![\Rightarrow mgh=\frac{1}{2}kx^2\quad [\text{x=compression in the spring}]\\\\\Rightarrow 10\times 9.8\times 5=\frac{1}{2}\cdot 100\cdot x^2\\\Rightarrow x=\sqrt{9.8}\\\Rightarrow x=3.13\ m](https://tex.z-dn.net/?f=%5CRightarrow%20mgh%3D%5Cfrac%7B1%7D%7B2%7Dkx%5E2%5Cquad%20%5B%5Ctext%7Bx%3Dcompression%20in%20the%20spring%7D%5D%5C%5C%5C%5C%5CRightarrow%2010%5Ctimes%209.8%5Ctimes%205%3D%5Cfrac%7B1%7D%7B2%7D%5Ccdot%20100%5Ccdot%20x%5E2%5C%5C%5CRightarrow%20x%3D%5Csqrt%7B9.8%7D%5C%5C%5CRightarrow%20x%3D3.13%5C%20m)
Thus, the spring compresses by 3.13 m.