Lets se
And


So

If spring constant is doubled mass must be doubled
 
        
             
        
        
        
Answer:
Explanation:
The frequency is 16.0 Hz. That means that 16 of these waves can pass a single point in 1 second. We are given frequency and wavelength. The equation that relates them is
 where f is frequency, v is velocity, and λ is wavelength. Putting all this together:
 where f is frequency, v is velocity, and λ is wavelength. Putting all this together:
 and solving for velocity,
 and solving for velocity,
v = 16.0(97.5) so
v = 1560 m/s. This wave can travel 1560 meters in a single second!!! Now that we know this velocity, we can use it in a proportion to find our unknown, which is how long, t, it will take to hear this sound 11000m away. (11 km is 11000m):
 and cross multiply to get
 and cross multiply to get
1560t = 11000 so
t = 7.1 seconds
 
        
             
        
        
        
Given 
Weight of the block A, Wa = 20 lb, weight of block B Wb = 50 lb. Applied
force to block A, P = 6lb, coefficient of static friction µs = 0.4, coefficient
of kinetic friction µk = 0.3. If a force P
is applied to the body, no relative motion will take place until the applied
force is equal to the force of friction Ff, which is acting opposite to the
direction of motion. Magnitude of static force of friction between block A and
block B, Fs = µsN, where N is
reaction force acting on block A. Now, resolve the forces Fx = max. P = (mA +
mB)a,
 
6 = (20 / 32.2 + 50 / 32.2)a 
 
2.173a = 6 
 
A = 2.76 ft/s^2 
 
To check slipping occurs between block A and block B, consider block A:
P – Ff = mAaA 
6 – Ff = 1.71 
Ff = 4.29 lb
 
And also,
N = wA. We know static friction, 
Fs = µsN 
Fs = 0.4 x 20 
Fs = 8lb 
Frictional force is less than static friction. Ff < Fs
<span>Therefors, acceleration of block A, aA = 2.76 ft/s^2, acceleration of
block B aB = 2.76 ft/s^2</span>
 
        
             
        
        
        
The angle of baking from the calculation is obtained as 30°.
<h3>What is banking?</h3>
The term banking refers to a means of preventing vehicles from skidding off the road at curves.
We know that the banking angle is obtained from;
θ = tan-1(v^2/rg)
v = 24.5 m/s 
r = 110 m
g = 9.8 m/s^2
θ = tan-1(25^2/9.8 * 110)
θ = tan-1(625 /1078)
θ = 30°
Learn more about the banking angle:brainly.com/question/26759099?r
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