Answer:
1. a, 99% b71%
2. 64%, 44%
3. Number of particles 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14
frequencies: 1, 2, 3, 12, 11, 15, 18, 10, 12, 4, 5, 3, 1, 2, 1
Relative frequencies 0.01, 0.02,0.03,0.12,0.11,0.15, 0.18,0.1, 0.12,0.04, 0.05,0.03,0.01,0.02,0.01
Step-by-step explanation:
Number of particles: 0, 1, 2, 3, 4, , 5, 6, 7
Frequency: 1, 2, 3, 12, 11, 15, 18, 10
Number of particles: 8, 9, 10, 11, 12, 13, 14
Frequency: 12, 4, 5, 3, 1, 2, 1
we solve by saying that . one of th smaples wafer is with any particles. we get the proportion by subtracting 1 from the total divided by 100
100-1/100
.99
at least five particles , then we can subtract the number of those with particles less than five from 100 , divided by 100
100-(11+12+3+2+1)=71/100
0.71 or 71%
b. those particles within 5 and 10 inclusive
15+18+10+12+4+5=64/100
0.64
0r 64%
five and 10 exclusively will be
18+10+12+4=44/100
0.44
44%
c. Draw an histogram. first we have frequency table first
Number of particles 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14
frequencies: 1, 2, 3, 12, 11, 15, 18, 10, 12, 4, 5, 3, 1, 2, 1
Relative frequencies 0.01, 0.02,0.03,0.12,0.11,0.15, 0.18,0.1, 0.12,0.04, 0.05,0.03,0.01,0.02,0.01
Relative frequencies is derived by dividing each frequencies over the total frequencies
wecan say that it is unimodal or say that it is slightly positively skewed
Step-by-step explanation:
Step 1: Multiply the whole number part (1) by the denominator (8).
1 × 8 = 8
Step 2: Add the product from Step 1 (8) to the numerator (4).
8 + 4 = 12
Step 3: Write that result (12) above the denominator. So,
Step 4: The fraction
Can be reduced by dividing both numerator and denominator by the GCD(12,8) = 4. Thus,
Answer:
{0.16807, 0.36015, 0.3087, 0.1323, 0.02835, 0.00243}
Step-by-step explanation:
The expansion of (p+q)^n for n = 5 is ...
(p+q)^5 = p^5 +5·p^4·q +10·p^3·q^2 +10·p^2·q^3 +5·p·q^4 +q^5
When the probability p=0.3 and q = 1-p = 0.7 the terms of this series correspond to the probabilities of 5, 4, 3, 2, 1, and 0 favorable outcomes out of 5 trials.
For example, p^5 = 0.3^5 = 0.00243 is the probability of 5 favorable outcomes in 5 trials where the probability of each favorable outcome is 0.3.
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The attachment shows the calculation of these numbers using a graphing calculator. It lists them in reverse order of the expansion of (p+q)^5 shown above, so that they are the probabilities of 0–5 favorable outcomes in the order 0–5.
