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yuradex [85]
3 years ago
9

 What is the volume of this cone?

Mathematics
1 answer:
bezimeni [28]3 years ago
4 0

Answer: C

Step-by-step explanation:

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How do you simplify 14/24
Bond [772]

Answer:

7/12

Step-by-step explanation:

Simplification is something we can do if both the numerator and denominator are divisible by the same number.

In 14/24, both numbers are divisible by 2.

So, we divide both the numerator and denominator by 2. We get 7/12.

Therefore 14/24 = 7/12.

7 0
3 years ago
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Reiki has 3/4 of a gallon of milk. She drinks one-third of the milk. How much milk does she drink?
hammer [34]
It should be 1/4 because one third of three fourths is one fourth. I hope this helps!
4 0
3 years ago
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Show me working please.
enyata [817]

Answer:

100% left handed people

20.6% = women

Not women who are left handed

=100-20.6

=79.4%

6 0
3 years ago
Hellohello, if you able to help me then please do. (:
otez555 [7]

Answer:

7 + 1.5 = 8.5

Step-by-step explanation:

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6 0
3 years ago
) f) 1 + cot²a = cosec²a​
notsponge [240]

Answer:

It is an identity, proved below.

Step-by-step explanation:

I assume you want to prove the identity. There are several ways to prove the identity but here I will prove using one of method.

First, we have to know what cot and cosec are. They both are the reciprocal of sin (cosec) and tan (cot).

\displaystyle \large{\cot x=\frac{1}{\tan x}}\\\displaystyle \large{\csc x=\frac{1}{\sin x}}

csc is mostly written which is cosec, first we have to write in 1/tan and 1/sin form.

\displaystyle \large{1+(\frac{1}{\tan x})^2=(\frac{1}{\sin x})^2}\\\displaystyle \large{1+\frac{1}{\tan^2x}=\frac{1}{\sin^2x}}

Another identity is:

\displaystyle \large{\tan x=\frac{\sin x}{\cos x}}

Therefore:

\displaystyle \large{1+\frac{1}{(\frac{\sin x}{\cos x})^2}=\frac{1}{\sin^2x}}\\\displaystyle \large{1+\frac{1}{\frac{\sin^2x}{\cos^2x}}=\frac{1}{\sin^2x}}\\\displaystyle \large{1+\frac{\cos^2x}{\sin^2x}=\frac{1}{\sin^2x}}

Now this is easier to prove because of same denominator, next step is to multiply 1 by sin^2x with denominator and numerator.

\displaystyle \large{\frac{\sin^2x}{\sin^2x}+\frac{\cos^2x}{\sin^2x}=\frac{1}{\sin^2x}}\\\displaystyle \large{\frac{\sin^2x+\cos^2x}{\sin^2x}=\frac{1}{\sin^2x}

Another identity:

\displaystyle \large{\sin^2x+\cos^2x=1}

Therefore:

\displaystyle \large{\frac{\sin^2x+\cos^2x}{\sin^2x}=\frac{1}{\sin^2x}\longrightarrow \boxed{ \frac{1}{\sin^2x}={\frac{1}{\sin^2x}}}

Hence proved, this is proof by using identity helping to find the specific identity.

6 0
3 years ago
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