Find the slope from the following table.<br> I need to finish this and I need some help.

Bob took 20 math test last year if he failed 6 of them what percent of the math test did he pass

kodGreya [7K]

6 out of 20=what percent?
6/20=x%

percent means parts out of 100
x%=x/100

6/20=x/100
time both sides by 100
30=x
answer is 30% passed

100-30=70
70% is answer

8 0

3 years ago

Read 2 more answers

A fast-food restaurant sold 54 burgers with cheese. If the ratio of burgers sold with cheese compared to without cheese was 9: 5

alex41 [277]

Answer:

Step-by-step explanation:

We can write an relationship for this as:

3

:

2

→

24

:

b

Where

b

is the number of burgers sold without cheese.

We can rewrite the relationship as an equation and solve for

b

:

3

2

=

24

b

2

3

=

b

24

×

2

3

=

24

×

b

24

48

3

=

24

×

b

24

16

=

b

=

16

The restaurant would of sold

16

burgers without cheese with the information provided in the problem.

4 0

2 years ago

Answer? i rlly dont know

Gnesinka [82]

Answer:

C

Step-by-step explanation:

i am smart

3 0

2 years ago

Help me please .......

snow_tiger [21]

Answer:

75%

Step-by-step explanation:

only interested in juniors

male 2

female 6

there are only 8 juniors and 6 of those are female

6/8 or 75%

5 0

3 years ago

Litter such as leaves falls to the forest floor, where the action of insects and bacteria initiates the decay process. Let A be

Travka [436]

Answer:

D = L/k

Step-by-step explanation:

Since A represents the amount of litter present in grams per square meter as a function of time in years, the net rate of litter present is

dA/dt = in flow - out flow

Since litter falls at a constant rate of L grams per square meter per year, in flow = L

Since litter decays at a constant proportional rate of k per year, the total amount of litter decay per square meter per year is A × k = Ak = out flow

So,

dA/dt = in flow - out flow

dA/dt = L - Ak

Separating the variables, we have

dA/(L - Ak) = dt

Integrating, we have

∫-kdA/-k(L - Ak) = ∫dt

1/k∫-kdA/(L - Ak) = ∫dt

1/k㏑(L - Ak) = t + C

㏑(L - Ak) = kt + kC

㏑(L - Ak) = kt + C' (C' = kC)

taking exponents of both sides, we have

$L - Ak = e^{kt + C'} \\L - Ak = e^{kt}e^{C'}\\L - Ak = C"e^{kt} (C" = e^{C'} )\\Ak = L - C"e^{kt}\\A = \frac{L}{k} - \frac{C"}{k} e^{kt}$

When t = 0, A(0) = 0 (since the forest floor is initially clear)

$A = \frac{L}{k} - \frac{C"}{k} e^{kt}\\0 = \frac{L}{k} - \frac{C"}{k} e^{k0}\\0 = \frac{L}{k} - \frac{C"}{k} e^{0}\\\frac{L}{k} = \frac{C"}{k} \\C" = L$

$A = \frac{L}{k} - \frac{L}{k} e^{kt}$

So, D = R - A =

$D = \frac{L}{k} - \frac{L}{k} - \frac{L}{k} e^{kt}\\D = \frac{L}{k} e^{kt}$

when t = 0(at initial time), the initial value of D =

$D = \frac{L}{k} e^{kt}\\D = \frac{L}{k} e^{k0}\\D = \frac{L}{k} e^{0}\\D = \frac{L}{k}$

4 0

2 years ago

Find the slope from the following table. I need to finish this and I need some help.