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iragen [17]
4 years ago
8

What is the decimal for 1 2

Mathematics
1 answer:
Rom4ik [11]4 years ago
4 0

The decimal for 1/2 is 0.5

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\sqrt{ 6+2 \sqrt{ 5 \phantom{\tiny{!}}} \phantom{\tiny{!}}} + \sqrt{ { \left(3+ \sqrt{ 5 \phantom{\tiny{!}}} \right) }^{ 2 } \ph
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Answer:

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WILL MARK BRAINLIEST!!!!!!! Use graphs and tables to find the limit and identify any vertical asymptotes of the function. limit
garri49 [273]

Answer:

see below

Step-by-step explanation:

lim x/ (x-4)

as x approaches 4 from the left

let x = 3.9

3.9/ (3.9-4) = -39

Let x = 3.99

3.99/ (3.99 - 4) =-399

As we get closer to 4 from the left we get larger and larger so we will get closer to - negative infinity

The limit as shown in the graph is negative infinity

The vertical asymptote is x=4

The horizontal symptote is y =1

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4 years ago
Find the surface area of the prism
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There are 6 faces to the prism:
2 each of (Length x Width): 2(4 x 4) = 2(16) = 32 m²
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2 each of (Width x Heighth): 2(4 x 8) = 2(32) = 64 m²

The sum of the faces is the Surface Area (S.A.)
32 m² + 64 m² + 64 m² = S.A.
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7 0
3 years ago
Eliza Savage received a statement from her bank showing a checking account balance of $324.18 as of January 18. Her own checkboo
Inessa [10]
Eliza started out with $324.18 on Jan. 18th and had outstanding cheques of $15.00+77.49+$124.28=$216.77. So her actual balance was $324.18-$216.77=$107.41. Now she has $487.38 so $487.38-$107.41=$379.97 balance for the deposited amount. 
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3 years ago
An individual who has automobile insurance from a certain company is randomly selected. Let Y be the number of moving violations
dimulka [17.4K]

Answer:

a. 0.80

b. $80

Step-by-step explanation:

a. The expected value, E(Y) is the sum of: [(each of the possible outcomes) × (the probability of the outcome occurring)]. In more concrete terms, the expectation is what you would expect the outcome of an experiment to be on average:

E(Y)=S_yP(Y=y)\\\\=0\times 0.5+1\times 0.25+2\times 0.20+3\times 0.05\\\\=0.80

Hence the expected value E(Y) is 0.80

b. From a above we have the expectation as  E(Y)=0.80.

-The expected amount is calculated by multiplying  expectation by the surcharge:

Ex \ Amount= E(Y)\times surcharge\\\\=0.80\times 100\\\\=80

Hence, the expected amount of surcharge is $80

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3 years ago
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