The slope is 4000/15 = 266.67
the the slope shows how far the helicopter went total
i hope this helps
Basically you can graph a function, for example a parabola by following the step pattern 1,35...
If you take the "standard" parabola, y = x², which has it's vertex at the origin (0, 0), then:
<span>➊ one way you can use a "step pattern" is as follows: </span>
<span>Starting from the vertex as "the first point" ... </span>
<span>OVER 1 (right or left) from the vertex point, UP 1² = 1 from the vertex point </span>
<span>OVER 2 (right or left) from the vertex point, UP 2² = 4 from the vertex point </span>
<span>OVER 3 (right or left) from the vertex point, UP 3² = 9 from the vertex point </span>
<span>OVER 4 (right or left) from the vertex point, UP 4² = 16 from the vertex point </span>
<span>and so on ... </span>
<span>where the "UP" numbers are the sequence of "PERFECT SQUARE" numbers ... </span>
<span>but always counting from the VERTEX EACH time. </span>
<span>➋ another way you can use a "step pattern" is just as you were doing: </span>
<span>Starting with the vertex as "the first point" ... </span>
<span>over 1 (right or left) from the LAST point, up 1 from the LAST point </span>
<span>over 1 (right or left) from the LAST point, up 3 from the LAST point </span>
<span>over 1 (right or left) from the LAST point, up 5 from the LAST point </span>
<span>over 1 (right or left) from the LAST point, up 7 from the LAST point </span>
<span>and so on ... </span>
<span>where the "UP" numbers are the sequence of "ODD" numbers ... </span>
<span>but always counting from the LAST point EACH time. </span>
<span>The reason why both Step Patterns Systems work is that set of PERFECT SQUARE numbers has the feature that the difference between consecutive members is the set of ODD numbers. </span>
<span>For your set of points, the vertex (and all the others) are simply "down 3" from the "standard places": </span>
<span>Standard {..., (-3, 9), (-2, 4), (-1, 1), (0, 0), (1, 1), (2, 4), (3, 9), ...} </span>
<span>shift ↓ 3 : {..., (-3, 6), (-2, 1), (-1, -2), (0, -3), (1,-2), (2, 1), (3, 6), ...} </span>
Answer:
4
Step-by-step explanation:
Let us consider an equilateral triangle ABC. Now, we will define midsegments:
A midsegment of a triangle is a segment that connects the midpoints of two sides of a triangle (here triangle ABC). This segment has two special properties. It is always parallel to the third side, and the length of the midsegment is half the length of the third side.
<em>Refer the attached image: </em>
Now, from the definition of midsegment we can see that:
and PQ is also parallel to BR.
Now, again from the definition of midsegment we can see that:
and QR is parallel to PB.
therefore, PQBR forms a parallelogram
And a diagonal of a parallelogram divides it into two congruent triangles.
Hence, triangle 2 (triangle PBR) is congruent to triangle 4(triangle PQR).
Similarly, triangle 3 (triangle QRC) and triangle 1 (triangle APQ) are congruent to triangle 4 (triangle PQR), Therefore, there are 4 congruent triangles formed when midsegments of an equilateral triangle partition the triangle.
Answer:
<u>2(3x + 4)</u>
Step-by-step explanation:
2 x 3x = 6x and 2 x 4 = 8
Plug the coordinates into the distance formula and solve.