Use this formula a2 − b2 = (a + b)(a − b)
<span>(x+1)^2-(x-1)^2 in this case, a = x+1, b = x-1</span>
<span>= [(x+1) + (x-1)] * [(x+1) – (x-1)]</span>
=(x +1 + x – 1) *(x +1 – x +1)
= 2x * 2
<span>=4x</span>
We have q < 0 < p < -r
Since q < 0, this means q is some negative number. The ordered pair (x,y) = (2,q) tells us that the point is below the x axis when x = 2. This does not fit graph B because it appears that an x intercept is at x = 2 (though the graph is a bit small so please provide larger versions of each graph if possible).
This does fit graph C because this point is below the x axis when x = 2.
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Then we have 0 < p or p > 0. So p is some positive number. The point (4,p) is some point above the x axis. We started with (2,q) being below the x axis and now we're above the x axis at (4,p). Only graph C fits this description.
Finally p < -r, so -r is some positive number larger than p. Therefore r itself is some negative number. Example: r = -10, -r = -(-10) = 10.
This means the point (6,r) is below the x axis. Once again this fits the description of what graph C is showing.
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<h3>So that is why graph C is the final answer.</h3>
Graphs A and D are ruled out because there is no transition from positive to negative or vice versa. Graph B is ruled out because of the x intercept at 2 (when that point should be below the x axis); however, the graph is a bit small so please provide a larger copy if possible. Thank you.
Answer: six square root of five minus four square root of fifteen
In symbolic form the answer looks like 
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Work Shown:
The basic idea is to distribute the outer term 
to each term inside. From there you simplify.
For the second to last step, I used the rule that 
I believe the answer is:
1+3.000000000i
I am making an educated guess, so sorry if I am wrong.
