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3 years ago

△1 is similar to △2. Which series of transformations can be used to transform △1 to △2?

Mathematics

1 answer:

olchik [2.2K]3 years ago

7 0

You can do it just believe in your self

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1,3,5,9,45

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3 years ago

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Lunna [17]

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3 years ago

In a study conducted in the United Kingdom about sleeping positions, 1000 adults in the UK were asked their starting position wh

earnstyle [38]

Answer:

$0.41 - 1.96\sqrt{\frac{0.41(1-0.41)}{1000}}=0.380$

$0.41 + 1.96\sqrt{\frac{0.41(1-0.41)}{1000}}=0.440$

The 95% confidence interval would be given by (0.380;0.440)

$0.41 - 2.58\sqrt{\frac{0.41(1-0.41)}{1000}}=0.370$

$0.41 + 2.58\sqrt{\frac{0.41(1-0.41)}{1000}}=0.450$

The 99% confidence interval would be given by (0.370;0.450)

Step-by-step explanation:

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 95% of confidence, our significance level would be given by $\alpha=1-0.95=0.05$ and $\alpha/2 =0.025$ . And the critical value would be given by:

$z_{\alpha/2}=-1.96, z_{1-\alpha/2}=1.96$

The confidence interval for the mean is given by the following formula:

$\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}$

If we replace the values obtained we got:

$0.41 - 1.96\sqrt{\frac{0.41(1-0.41)}{1000}}=0.380$

$0.41 + 1.96\sqrt{\frac{0.41(1-0.41)}{1000}}=0.440$

The 95% confidence interval would be given by (0.380;0.440)

And for the 99% confident interval the critical value would be 2.58 and if we replace we got:

$0.41 - 2.58\sqrt{\frac{0.41(1-0.41)}{1000}}=0.370$

$0.41 + 2.58\sqrt{\frac{0.41(1-0.41)}{1000}}=0.450$

The 99% confidence interval would be given by (0.370;0.450)

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3 years ago

Find a power series for f(x)=xln(1+x). \[f(x)=xln(1+x)\]. \[\frac{d}{dx}xln(1+x)\]. \[=\frac{x}{x+1}+ln(x+1)\]. \[=\sum_{n=0}^{\

Anastaziya [24]

In your question that first im confused but i arrange if correctly though, in my calculation the possible power of the series is infinity <span>∑ n-0 times the -1 one to the power of n over n+1 times x to the power of n+2</span>

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3 years ago