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deff fn [24]
2 years ago
15

What numbers make this expression undefined x^2+3/x^2-11x-12

Mathematics
1 answer:
marusya05 [52]2 years ago
5 0

\frac{ {x}^{2}  + 3}{ {x}^{2}  - 11x - 12}

Because which numbers will make the expessions undefined. We will focus on the denominator only.

Factor the terms.

(x - 12)(x + 1)

Now which 2 numbers that will make these terms become 0?

12 and - 1 of course.

So these 2 numbers that will make the expressions undefined are 12 and - 1

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Answer and working out please!
frosja888 [35]

Answer:

17.0710678119 and 2.92893218813

Step-by-step explanation:

Theoretically, the wire should come out to be x+y=80,

and the sum of the areas of the squares should be (x/4)^2+(y/4)^2=300.

x/4 and y/4 being the length of one side of the square, we would then square that to find the area. The total wire is all x+y=80. X being one part and Y being the other.

Theoretically, using systems. i found the answers: 68.2842712474619,11.715728752538098

Again, these numbers are very large, and I they actually do both add up to each amount basically perfectly. If your teacher is asking for a rounded answer, that would've been helpful to know. But again, theoretically, those are the answers.

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3 years ago
14 1/5 - 5 5/6 as a fraction
melomori [17]

Answer:

\frac{251}{30} or 8\frac{11}{30}

Step-by-step explanation:

4 0
3 years ago
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<img src="https://tex.z-dn.net/?f=5x-%20%5Cdfrac%7B%20%5Csqrt%7B%209%20%7B%20x%20%7D%5E%7B%202%20%7D%20-6x%2B1%20%5Cphantom%7B%5
Morgarella [4.7K]

Answer:

=5x+1          or          =5x-1

Step-by-step explanation:

One is given the following equation:

5x-\frac{\sqrt{9x^2-6x+1}}{1-3x}

The problem asks one to simplify the expression, the first step in solving this equation is to factor the equation.  Rewrite the numerator and denominator of the fraction as the product of two expressions. Remember the factoring patterns:

(a-b)^2=a^2-2ab+b^2

=5x-\frac{\sqrt{9x^2-6x+1}}{1-3x}

=5x-\frac{\sqrt{(3x-1)^2}}{-(3x-1)}

Now simplify the numerator. Remember, taking the square root of a squared value is the same as taking the absolute value of the expression,

=5x-\frac{\sqrt{(3x-1)^2}}{1-3x}

=5x-\frac{|3x-1|}{-(3x-1)}

Rewrite the expression without the absolute value sign in the numerator. Remember the general rule for removing the absolute value sign:

|a-b|\\=a -b           or           (-a-b) = b-a

=5x-\frac{|3x-1|}{-(3x-1)}

=5x-\frac{3x-1}{-(3x-1)}          or          =5x-\frac{-(3x-1)}{-(3x-1)}

Simplify both expressions, reduce by canceling out common terms in both the numerator and the denominator,

=5x-\frac{3x-1}{-(3x-1)}          or          =5x-\frac{-(3x-1)}{-(3x-1)}

=5x-(-1)          or          =5x-(1)

Simplify further by rewriting the expression without the parenthesis, remember to distribute the sign outside the parenthesis by the terms inside of the parenthesis; note that negative times negative equals positive.

=5x-(-1)          or          =5x-(1)

=5x+1          or          =5x-1

6 0
3 years ago
Find the root<br><br> X^3-125=0
Firlakuza [10]

Steps to solve:

x^3 - 125 = 0

~Add 125 to both sides

x^3 = 125

~Take cube root of both sides

x = 5

Best of Luck!

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photoshop1234 [79]

To find the diameter of a circle, using only the circumference, you need to divide the circumference by π, or 3.14.

So in this case, you must divide 12 by 3.14, which gives you 3.82.

I even double checked this, and should be correct then.

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3 years ago
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