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3 years ago

Please Help me !!Q 1,2,3

Mathematics

1 answer:

Virty [35]3 years ago

4 0

The area of a parallelogram is the product of the length of the base and the height measured perpendicular to the base.

1i) (20 cm)*(12 cm) = 240 cm^2

2ii) (7 cm)*(7.5 cm) = 52.5 cm^2

3iii) 27 cm^2 = (6 cm)*h
.. h = (27 cm^2)/(6 cm) = 4.5 cm

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Ahat [919]

Answer:

I'm not sure

Step-by-step explanation:

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2 years ago

Given F(x) = 3x 2 - 4, find F(-√3). a)-13 b)5 c)23

svet-max [94.6K]

I want to say 5 but I'm not sure

8 0

3 years ago

Read 2 more answers

Can someone just please explain why in PEMDAS for example: 6 + 9 ÷ 3 × 7. Why do you do the division (9/3) before the multiplica

Grace [21]

Because is division is before multiplication you have to do division even though the m is before d.

7 0

3 years ago

Please someone help me to prove this.

morpeh [17]

Answer: see proof below

Step-by-step explanation:

Use the Double Angle Identity: sin 2Ф = 2sinФ · cosФ

Use the Sum/Difference Identities:

sin(α + β) = sinα · cosβ + cosα · sinβ

cos(α - β) = cosα · cosβ + sinα · sinβ

Use the Unit circle to evaluate: sin45 = cos45 = √2/2

Use the Double Angle Identities: sin2Ф = 2sinФ · cosФ

Use the Pythagorean Identity: cos²Ф + sin²Ф = 1

Proof LHS → RHS

LHS: 2sin(45 + 2A) · cos(45 - 2A)

Sum/Difference: 2 (sin45·cos2A + cos45·sin2A) (cos45·cos2A + sin45·sin2A)

Unit Circle: 2[(√2/2)cos2A + (√2/2)sin2A][(√2/2)cos2A +(√2/2)·sin2A)]

Expand: 2[(1/2)cos²2A + cos2A·sin2A + (1/2)sin²2A]

Distribute: cos²2A + 2cos2A·sin2A + sin²2A

Pythagorean Identity: 1 + 2cos2A·sin2A

Double Angle: 1 + sin4A

LHS = RHS: 1 + sin4A = 1 + sin4A $\checkmark$

6 0

3 years ago

In this figure, 52. 9% of the area is painted yellow. How much of the area is painted yellow?22. 218 in²25. 921 in²44. 436 in²48

Paraphin [41]

Answer:

its 48.139

Step-by-step explanation:

i also needed help , but i only saw this so i guessed the answer and it is 48.139.

5 0

2 years ago