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Solnce55 [7]
3 years ago
11

What is the slope if the line through the points 2/3, 4/7 and 2/3, 11/7

Mathematics
1 answer:
Umnica [9.8K]3 years ago
6 0

The fromula of a slope:

m=\dfrac{y_2-y_1}{x_2-x_1}

We have the points \left(\dfrac{2}{3},\ \dfrac{4}{7}\right) and \left(\dfrac{2}{3},\ \dfrac{11}{7}\right)

Substitute:

m=\dfrac{\frac{11}{7}-\frac{4}{7}}{\frac{2}{3}-\frac{2}{3}}=\dfrac{\frac{7}{7}}{0}\ !!!!

<h3>Answer: slope is undefined.</h3><h3 />

It's a vertical line: x=\dfrac{2}{3}

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Step-by-step explanation:

Hey there!

The given point is (8,-3) as (x1,y1) and slope (m) = -3/4.

<u>Note</u><u>:</u><u> </u><u>use</u><u> </u><u>one</u><u> </u><u>po</u><u>int</u><u> formula</u><u> for</u><u> </u><u>f</u><u>inding</u><u> </u><u>the</u><u> </u><u>eq</u><u>uation</u><u>.</u>

(y - y1) = m(x - x1)

<u>Pu</u><u>t</u><u> all</u><u> values</u><u>.</u>

<u>(y  + 3) =  -  \frac{ 3}{4} (x - 8)</u>

<u>Sim</u><u>plify</u><u> it</u><u>.</u>

<u>(y + 3) =   -  \frac{  3}{4} x - 8 \times  -  \frac{3}{4}</u>

<u>(y + 3) =  -  \frac{3}{4} x + 6</u>

<u>y  =  -  \frac{3}{4} x + 6 - 3</u>

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<u>There</u><u>fore</u><u>,</u><u> </u><u>the</u><u> </u><u>equation</u><u> is</u><u>;</u><u> </u><u>y</u><u> </u><u>=</u><u> </u><u>-</u><u>3</u><u>/</u><u>4</u><u>x</u><u>+</u><u>3</u><u>.</u>

<em><u>Hope</u></em><em><u> </u></em><em><u>it</u></em><em><u> helps</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>

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