Answer:
2 < x < 4.5
Step-by-step explanation:
10<2+4x<20
We need to isolate x
Subtract 2 from all sides
10-2<2-2+4x<20-2
8<4x<18
Divide all sides by 4
8/4<4x/4<18/4
2 < x < 9/2
2 < x < 4.5
Answer:
b
Step-by-step explanation:
Area of the shaded region =[ (3x-2)(x+3) ] - [ x*6 ]
= 3x*x +3x*3 + (-2)*x + (-2)*3 - 6x
=3x² + 9x - 2x - 6 - 6x {bring like term together}
=3x² + 9x - 2x - 6x - 6
= 3x² + x - 6 {9x - 2x - 6x = 9x - 8x = x}
Area = 24 square units
3x² + x - 6 = 24
3x² + x - 6 - 24 = 0
3x² + x - 30 = 0
Product = 3* -30 = -90
Sum = 1
Factors = 10 , (-1)
3x² + x - 30 = 0
3x² - 9x + 10x - 10*3 = 0
3x*(x - 3) +10*(x - 3) = 0
(x-3)(3x +10) = 0
3x + 10 is ignored because measurements will not be in negative values.
x - 3 = 0
x = 3
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Answer:
27 dimes
Step-by-step explanation:
2.70/.10=27
Answer:
V(x,y,z) ≈ 61.2 in
Step-by-step explanation:
for the function f
f(X)=x³
then the volume will be
V(x,y,z)= f(X+h) - f(X) , where h= 0.2 (thickness)
doing a Taylor series approximation to f(x+h) from f(x)
f(X+h) - f(X) = ∑fⁿ(X)*(X-h)ⁿ/n!
that can be approximated through the first term and second
f(X+h) - f(X) ≈ f'(x)*(-h)+f''(x)*(-h)²/2 = 3*x²*(-h)+6*x*(-h)²/2
since x=L=10 in (cube)
f(X+h) - f(X) ≈ 3*x²*(-h)+6*x*(-h)²/2 = 3*L²*h+6*L*h²/2 = 3*L*h*(h+L)
then
f(X+h) - f(X) ≈ 3*L*h*(h+L) = 3* 10 in * 0.2 in * ( 0.2 in + 10 in ) = 61.2 in
then
V(x,y,z) ≈ 61.2 in
V real = (10.2 in)³-(10 in)³ = 61 in
