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Flauer [41]
3 years ago
13

It took h to complete 1 game of cards. How many games can be completed in h?

Mathematics
1 answer:
dmitriy555 [2]3 years ago
7 0

If it took one hour to complete a card game, we can tell that the average play time varies around that time.

So only one game can be completed in one hour.

Hope it helped,

Happy homework/ study/ exam!

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Please, help me in this!! It's very difficult for me. I'm doing assignments in edgeunuity. Please help me in my assignment!!!
marusya05 [52]

Answer:

Inclined plane= 1st option

Wheel and axle= 2nd option

Wedge= 5th option

Pulley= 3rd option

Lever= 4th option

8 0
3 years ago
21 ≤ 2x + 3 = <br> How do you work this out? And what is the answer? :)
Igoryamba
Just use app called Socratic will help out
4 0
3 years ago
Read 2 more answers
What is the difference?
Crazy boy [7]

Answer:

<h2>D. \frac{x^{2}+3x-12 }{(x-5)(x+3)(x+7)} \\ or StartFraction x squared + 3 x minus 12 Over (x + 3) (x minus 5) (x + 7) EndFraction</h2>

Step-by-step explanation:

Given the expression \frac{x}{x^{2}-2x-15 } - \frac{4}{x^{2} + 2x - 35 }, the dfference is expressed as follows;

Step1: First we need to factorize the denominator of each function.

\frac{x}{x^{2}-2x-15 } - \frac{4}{x^{2} + 2x - 35 }\\= \frac{x}{x^{2}-5x+3x-15 } - \frac{4}{x^{2} + 7x-5x - 35 }\\= \frac{x}{x(x-5)+3(x-5) } - \frac{4}{x( x+ 7)x-5(x +7) }\\= \frac{x}{(x-5)(x+3) } - \frac{4}{(x-5)(x +7) }\\\\

Step 2: We will find the LCM of the resulting expression

=  \frac{x}{(x-5)(x+3) } - \frac{4}{(x-5)(x +7) }\\= \frac{x(x+7)-4(x+3)}{(x-5)(x+3)(x+7)} \\= \frac{x^{2}+7x-4x-12 }{(x-5)(x+3)(x+7)} \\= \frac{x^{2}+3x-12 }{(x-5)(x+3)(x+7)} \\

The final expression gives the difference

6 0
4 years ago
2y+3x=90 what is x and y
yan [13]

If x=-6 then y=54.
If x=-4 then y=51.
If x=-2 then y=48.
If x=0 then y=45.
If x=2 then y=42.
If x=4 then y=39.
If x=6 then y=36.

There are an infinite variety of pairs of numbers for 'x' and 'y'
that can make that equation true.

You can use that equation to draw a  line on a graph.  Then
EVERY point on the line is a solution to the equation.

'x' and 'y' don't have single values unless you have TWO equations.

4 0
3 years ago
A) Factorise a^2 - b^2​
Vadim26 [7]

Answer:

a·a-b·b

Step-by-step explanation:

7 0
3 years ago
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