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The sequence 3, 1,1/3 is a geometric sequence
The 7th term of the sequence is 1/243
<h3>How to determine the 7th term?</h3>
The sequence is given as:
3, 1,1/3
The above sequence is a geometric sequence with the following parameters:
- First term, a= 3
- Common ratio, r = 1/3
The nth term is then calculated as:
Tn = ar^(n-1)
So, the 7th term is:
T7 = ar^6
Substitute known values
T7 = 3 * (1/3)^6
This gives
T7 = 1/3^5
Evaluate
T7 = 1/243
Hence, the 7th term of the sequence is 1/243
Read more about geometric sequence at:
brainly.com/question/24643676
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