558 gallons are used when the car has been driven 18 miles.
<u>Step-by-step explanation:</u>
<u>From the given data, it can be determined that :</u>
- The number of gallons for 2 miles = 62 gallons
- The number of gallons for 4 miles = 124 gallons
- The number of gallons for 10 miles = 310 gallons
Let, the number of gallons for 18 miles = 'x' gallons
<u>To find x :</u>
compare the given data with the unknown data,
62 gallons / 2 miles = x gallons / 18 miles
keep x alone on one side,
x = (62×18) / 2
x = 31×18
x = 558 gallons
Therefore, 558 gallons are used to drive 18 miles.
Answer:
and 
Step-by-step explanation:
(a)
A = 
× 4
× 
= 2 ×
= 
× 
← rationalise the denominator
= units²
(b)
Using Pythagoras' identity in the right triangle
let hypotenuse be h , then
h² = (4 )² + ( )²
= 32 + 
= 
+
= 
( take the square root of both sides )
h = 
= 
× ← rationalise the denominator
h =
9514 1404 393
Answer:
- 2nd force: 99.91 lb
- resultant: 213.97 lb
Step-by-step explanation:
In the parallelogram shown, angle B is the supplement of angle DAB:
∠B = 180° -77°37' = 102°23'
Angle ACB is the difference of angles 77°37' and 27°8', so is 50°29'.
Now, we know the angles and one side of triangle ABC. We can use the law of sines to solve for the other two sides.
BC/sin(A) = AB/sin(C)
AD = BC = AB·sin(A)/sin(C) = (169 lb)sin(27°8')/sin(50°29') ≈ 99.91 lb
AC = AB·sin(B)/sin(C) = (169 lb)sin(102°23')/sin(50°29') ≈ 213.97 lb
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