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3 years ago

Simplify 63+4+23(15)+*2

Mathematics

1 answer:

Angelina_Jolie [31]3 years ago

5 0

Answer:

114.

Step-by-step explanation:

remove parenthesis
multiply the numbers 6 x 3 + 18

18 + 4 + 2 x 3 x 15 + 2

multiply the numbers 2 x 3 x 15 + 90

18 + 4 + 2 + 90 + 2

add the numbers : 18 + 4 + 2 + 90 + 2

= 114!

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Past records indicate that the probability of online retail orders

Tcecarenko [31]

Answer:

a) Mean = 1.6, standard deviation = 1.21

b) 18.87% probability that zero online retail orders will turn out to be fraudulent.

c) 32.82% probability that one online retail order will turn out to be fraudulent.

d) 48.31% probability that two or more online retail orders will turn out to be fraudulent.

Step-by-step explanation:

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

The mean of the binomial distribution is:

$E(X) = np$

The standard deviation of the binomial distribution is:

$\sqrt{V(X)} = \sqrt{np(1-p)}$

In this problem, we have that:

$p = 0.08, n = 20$

a. What are the mean and standard deviation of the number of online retail orders that turn out to be fraudulent?

Mean

$E(X) = np = 20*0.08 = 1.6$

Standard deviation

$\sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{20*0.08*0.92} = 1.21$

b. What is the probability that zero online retail orders will turn out to be fraudulent?

This is P(X = 0).

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{20,0}.(0.08)^{0}.(0.92)^{20} = 0.1887$

18.87% probability that zero online retail orders will turn out to be fraudulent.

c. What is the probability that one online retail order will turn out to be fraudulent?

This is P(X = 1).

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 1) = C_{20,1}.(0.08)^{1}.(0.92)^{19} = 0.3282$

32.82% probability that one online retail order will turn out to be fraudulent.

d. What is the probability that two or more online retail orders will turn out to be fraudulent?

Either one or less is fraudulent, or two or more are. The sum of the probabilities of these events is decimal 1. So

$P(X \leq 1) + P(X \geq 2) = 1$

We want $P(X \geq 2)$

$P(X \geq 2) = 1 - P(X \leq 1)$

In which

$P(X \leq 1) = P(X = 0) + P(X = 1)$

From itens b and c

$P(X \leq 1) = 0.1887 + 0.3282 = 0.5169$

$P(X \geq 2) = 1 - P(X \leq 1) = 1 - 0.5169 = 0.4831$

48.31% probability that two or more online retail orders will turn out to be fraudulent.

4 0

4 years ago

-3/4(8n+12)=3(n-3) show work pls

Nastasia [14]

Answer: n = 0

Step-by-step explanation:

Given expression

(-3/4) (8n + 12) = 3 (n - 3)

Expand parentheses and apply the distributive property

-6n - 9 = 3n - 9

Add 9 on both sides

-6n - 9 + 9 = 3n - 9 + 9

-6n = 3n

Subtract 3n on both sides

-6n - 3n = 3n - 3n

-9n = 0

Divide -9 on both sides

-9n / -9 = 0 / -9

$\boxed{n=0}$

Hope this helps!! :)

Please let me know if you have any questions

5 0

3 years ago

Pls help #1 isjsbijsj

grigory [225]

Answer:

The value of “Y” is (6)

Step-by-step explanation:

the x value unit of “5” has the y value of “6.”

5 0

3 years ago

Read 2 more answers

Evaluate the function at x = -4. f(x) = sqrt 2x²-7

Juliette [100K]

Answer: 16 $\sqrt{2}$ -7

Step-by-step explanation:

6 0

3 years ago

Let A = {Dirk, Johan, Frans, Sarie}, B = {Frans, Sarie, Tina, Klaas, Henrika}, C = {Hans, Frans}. Find the number indicated. n(A

olchik [2.2K]

Answer:

$\boxed{ \bold{ \huge{ \boxed{ \bold{9}}}}}$

Step-by-step explanation:

Given,

A = { Dirk , Johan , Frans , Sarie }

B = { Frans , Sarie , Tina , Klass , Henrika }

To find : n ( A ) + n ( A )

Now, count the number of member of a set A

n ( A ) = 4

Also, Count the number of members of a set B

n ( B ) = 5

Finding n( A ) + n ( B )

= 4 + 5

= 9

Hope I helped!

Best regards! :D

6 0

3 years ago

Simplify 6*3+4+2*3(15)+*2

Simplify 63+4+23(15)+*2