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Tomtit [17]
3 years ago
9

David has some marbles.He gave 2/5 of his marble to his neighbour and 1/6 of the remainder to his friend Ali.He had 25 marbles l

eft.How many marbles did he have at first?
Mathematics
1 answer:
babunello [35]3 years ago
7 0

Answer: he had 50 marbles at first.

Step-by-step explanation:

Let x represent the number of marbles that he had at first.

He gave 2/5 of his marble to his neighbour. It means that the number of marbles that he gave to his neighbour is 2/5 × x = 2x/5

The number of marbles that he has remaining is

x - 2x/5 = 3x/5

He gave 1/6 of the remainder to his friend Ali. It means that the number of marbles that he gave to his friend is

1/6 × 3x/5 = x/10

The number of marbles that he has left is

3x/5 - x/10 = 5x/10

He had 25 marbles left. It means that

5x/10 = 25

5x = 25 × 10 = 250

x = 250/5 = 50

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3 years ago
Identify the special name for ∠3 and ∠10
quester [9]

Answer:

square roots ?

Step-by-step explanation:

8 0
2 years ago
PLEASE HELP ASAP!! WILL GIVE BRAINLIEST!!
zhenek [66]

Given is :

The area of the rectangular patio is = 130 square feet

Let the width of the patio be = x feet

As length is 3 feet more than the width, so the length is = x+3 feet

Now area of rectangle is = length * width

x(x+3)=130

x^{2}+3x=130

x^{2}+3x-130=0

x^{2}+13x-10x-130=0

x(x+13)-10(x+13)=0

(x-10)(x+13)=0

This gives either x-10=0 or x+13=0

x-10=0 ; x=10

x+13=0 ; x=-13 (neglect this negative value)

So, the width of the patio is = 10 feet

Length = 10+3 = 13 feet

7 0
3 years ago
6(k+8)=96<br> k=12 k=-4<br> k=9<br> k=8
olchik [2.2K]

Answer:

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Step-by-step explanation:

B

5 0
3 years ago
Eli attended a concert. The decibel level of the music averaged 110 decibels but varied by 28 decibels from the average. Enter a
musickatia [10]

Answer:

The decibel range is   82\leq d\leq 138

Step-by-step explanation:

Let

d -----> the decibel level of the music

we know that

The absolute value of the difference of the decibel level of the music and its average, must be less than or equal to 28 decibels

so

The absolute value that represent this problem is

\left|d-110\right|\le28

Solve the absolute value

<em>First solution (positive)</em>

+(d-110)\le28

Adds 110 both sides

d\le28+110

d\le138

<em>Second solution (negative)</em>

-(d-110)\le28

Multiply by -1 both sides

(d-110)\ge-28

Adds 110 both sides

d\ge-28+110

d\ge82

therefore

The decibel range is

82\leq d\leq 138

8 0
3 years ago
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