Hello,
I believe it is true.
Hope this helped!
Answer:
See below.
Step-by-step explanation:
The graph of the quadratic equation is a parabola or u shaped graph. It has a vertex at (-1,-3) since h=-1 and k=-3 in the vertex form. It is also facing down since the leading coefficient is negative.
Answer:
The first five terms of the given sequence
3, 6, 11, 18, 27
Step-by-step explanation:
It is given that,
an=n² +2
<u>To find the first five terms</u>
a₁ = 1² + 2 = 1 + 2 = 3
a₂ = 2² + 2 = 4 + 2 = 6
a₃ = 3² + 2 = 9 + 2 = 11
a₄ = 4² + 2 = 16 + 8 = 18
a₅ = 5² + 2 = 25 + 2 = 27
Therefore the first five terms of the given sequence
3, 6, 11, 18, 27
Answer:-32 I THINK IM NOT 100 PERCENT POSITIVE
Step-by-step explanation:
Answer:
Below
Step-by-step explanation:
sin(2x) = 2 ×cos(x)× sin(x)
● sin(x) = 2 × cos(x) × sin(x)
● 2 × cos(x) = 1
● cos (x) = 1/2
So we can deduce that:
● x = Pi/3 + 2*k*Pi
● or x = -Pi/3 + 2*k*Pi
K is an integer
