Find the 50th term of 15, 9, 3, -3,...

pentagon [3]

So you can scan it here and it will give you the sotoiun and answers just make sure u show ur workkk good luck

4 0

3 years ago

The relation of 10 squares to 100 squares can be expressed in many ways. Which of the following is not a way to express the rela

irakobra [83]

Answer:

As there are no options given in the question, but the options in the complete question are;

a) 2/10b) 20%c) 0.02d) 0.2

So, from the given options "c" is not a way to express this.

we can write 20/100 as 2/10 so option a is a way to express given relationship. and if we look at option b, it is also a way to express 20 from 100 is 20%. And if we divide, we get 20/100 = 2/10 = 0.2, so d is also a way to express given relationship. Thus, c is the answer.

Step-by-step explanation:As there are no options given in the question, but the options in the complete question are;

a) 2/10b) 20%c) 0.02d) 0.2

So, from the given options "c" is not a way to express this.

we can write 20/100 as 2/10 so option a is a way to express given relationship. and if we look at option b, it is also a way to express 20 from 100 is 20%. And if we divide, we get 20/100 = 2/10 = 0.2, so d is also a way to express given relationship. Thus, c is the answer.

3 0

2 years ago

Read 2 more answers

Let f(x)=x^2+5x−36. Enter the x-intercepts of the quadratic function in the boxes.___and__

Zolol [24]

Given

$f(x)=x^2+5x-36$

8 0

1 year ago

Z=y+mx. Solve for x. I need the answer fast

Simora [160]

If you want x, rearrange Z=y+mx as follows: mx = z - y. Then div. all 3 terms by m:
z-y
x = ------- (answer).
m

8 0

3 years ago

Assume the upper arm length of males over 20 years old in the United States is approximately Normal with mean 39.2 centimeters (

MAVERICK [17]

Answer:

The interval [32.6 cm, 45.8 cm]

Step-by-step explanation:

According with the 68–95–99.7 rule for the Normal distribution: If $\large \bar x$ is the mean of the distribution and s the standard deviation, around 68% of the data must fall in the interval

$\large [\bar x - s, \bar x +s]$

around 95% of the data must fall in the interval

$\large [\bar x -2s, \bar x +2s]$

around 99.7% of the data must fall in the interval

$\large [\bar x -3s, \bar x +3s]$

So, the range of lengths that covers almost all the data (99.7%) is the interval

[39.2 - 3*2.2, 39.2 + 3*2.2] = [32.6, 45.8]

This means that if we measure the upper arm length of a male over 20 years old in the United States, the probability that the length is between 32.6 cm and 45.8 cm is 99.7%

3 0

3 years ago