2:3:1
2+3+1 = 7
£72 / 7 = £10.28
Answer:
£10.28 * 2 = £20.56
£10.28 * 3 = £30.84
£10.28 * 1 = £10.28
If you want to check if it's correct. add all three of them and see if you get the £72.
Please make this answer the brainiest!
Answer:
17) MC(x) = 35 − 12/x²
18) R(x) = -0.05x² + 80x
Step-by-step explanation:
17) The marginal average cost function (MC) is the derivative of the average cost function (AC).
AC(x) = C(x) / x
MC(x) = d/dx AC(x)
First, find the average cost function:
AC(x) = C(x) / x
AC(x) = (5x + 3)(7x + 4) / x
AC(x) = (35x² + 41x + 12) / x
AC(x) = 35x + 41 + 12/x
Now find the marginal average cost function:
MC(x) = d/dx AC(x)
MC(x) = 35 − 12/x²
18) x is the demand, and p(x) is the price at that demand. Assuming the equation is linear, let's use the points to find the slope:
m = (40 − 50) / (800 − 600)
m = -0.05
Use point-slope form to find the equation of the line:
p(x) − 50 = -0.05 (x − 600)
p(x) − 50 = -0.05x + 30
p(x) = -0.05x + 80
The revenue is the product of price and demand:
R(x) = x p(x)
R(x) = x (-0.05x + 80)
R(x) = -0.05x² + 80x
In order to know at what price the two services offered would be the same, we can actually use the process of trial and error starting from 1 onwards. The first one is 50.45 per month plus a standard fee of 60 for installation. So this will be 60+50.45x (number of days). After that. there is the other one that has free installation but charges 57.95. So it can be expressed as 57.95x. Now after trial and error with numbers as x, I came upon 8. If x is 8, then the first one will be 60+50.45 (8) = 463.6. For the second, 57.95(8) will also equal to 463.6. So the day in which the two services will charge the same is during the 8th day.
