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Elanso [62]
3 years ago
9

Simplify:

Mathematics
2 answers:
OlgaM077 [116]3 years ago
8 0
   4x + 5                          5x                     4x + 5 - 5x                 -x + 5
----------------     -      ----------------     =     ------------------   =  -------------------
6x^2 - x - 12             6x^2 - x - 12            6x^2 - x - 12           6x^2 - x - 12

galina1969 [7]3 years ago
4 0

Answer:

\frac{-x+5}{6x^2-x-12}}

Step-by-step explanation:

\frac{4x+5}{6x^2-x-12} - \frac{5x}{6x^2-x-12}

To subtract fractions the denomintors should be same

Here the denominator are same

so we combine the numerators and put denominator only once

\frac{4x+5-5x}{6x^2-x-12}}

Combine like terms

\frac{-x+5}{6x^2-x-12}}

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Assume that the heights of men are normally distributed with a mean of 69.0 inches and a standard deviation of 2.8 inches. If th
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Answer:

The bottom cutoff heights to be eligible for this experiment is 66.1 inches.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

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Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

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What is the bottom cutoff heights to be eligible for this experiment?

The bottom 15% are excluded, so the bottom cutoff is the 15th percentile, which is X when Z has a pvalue of 0.15. So X when Z = -1.037.

Z = \frac{X - \mu}{\sigma}

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The bottom cutoff heights to be eligible for this experiment is 66.1 inches.

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