Items bought:
x packs of pencils
twice as many packs of erasers, number of packs of erasers = 2x
three times as many rolls of tape, number of rolls of tape = 3x
Now, we have two possible scenarios:
1- The three items cost the same:
cost of one pack of pencils = cost of one pack of erasers = cost of one roll of tape = m
total amount spent = xm + 2xm + 3xm = 6xm
2- The three items do not cost the same:
cost of one pack of pencils = m
cost of one pack of erasers = n
cost of one roll tape = p
total amount spent = xm + 2xn + 3xp = x(m + 2n + 3p)
Answer:
That's an isosceles right trapezoid. The legs equal hypotenuse * (1 / sq root (2))
legs = 7 * 1 / sqroot (2)
Answer is D
Step-by-step explanation:
Answer:
Arithmetic sequence
Step-by-step explanation:
-We notice that the difference between the number of favors already given out between any two consecutive number of party guests has an additive increment.
-This increment is called the Common Difference and has a value of 3.
-The number of tickets available is 50.
Hence, the number of tickets already given out can be calculated using the formula:
Hence, this is an Arithmetic Sequence.
It’s gonna be radical 10x/ 4x.
The sum of them is 16,910 would be your answer