Answer:
C. 2.
Step-by-step explanation:
The graph descends from the left so the coefficient of the leading term is negative. It is also a cubic equation with zeros of -20, about 6.5 and about 13. so we can write the equation as below. The last 2 values can only be guessed because the x axis only shows values which are multiples of 5.
f(x) = a(x + 20)(x - 6.5)(x - 13) where a is a negative constant.
(This is only an approximation).
By the Remainder theorem, when the expression is divided by (x + 10):
f(-10) = -20 so we have
-20 = a (-10 + 20)(-10-6.5)(-10 - 13)
(10)(-16.5)(-23)a = -20
a = -20 / (10)(-16.5)(-23)
a = -0.0053
When the equation is divided by (x - 10) then f(10) is the remainder so substituting we have as the remainder:
-0.0053(10+20)(10-6.5)(10 -13)
-0.0053 * 30 * 3.5 * -3
= 1.7 approximately.
Looks like the answer is 2.
Answer:
.8 or 4/5ths cup
Step-by-step explanation:
divide number of bottles by cups
4 1/2 is 4.5
5 5/8 is 5.625
4.5/5.625 = .8 (or 4/5ths)
Answer:
-729
Step-by-step explanation:



Answer:
V = 63π / 200 m^3
Step-by-step explanation:
Given:
- The function y = f(x) is revolved around the x-axis over the interval [1,6] to form a spherical surface:
y = √(42*x - x^2)
- The surface is coated with paint with uniform layer thickness t = 1.5 mm
Find:
The volume of paint needed
Solution:
- Let f be a non-negative function with a continuous first derivative on the interval [1,6]. The Area of surface generated when y = f(x) is revolved around x-axis over the interval [1,6] is:
![S = 2*\pi \int\limits^a_b { [f(x)*\sqrt{1 + f'(x)^2} }] \, dx](https://tex.z-dn.net/?f=S%20%3D%202%2A%5Cpi%20%5Cint%5Climits%5Ea_b%20%7B%20%5Bf%28x%29%2A%5Csqrt%7B1%20%2B%20f%27%28x%29%5E2%7D%20%7D%5D%20%5C%2C%20dx)
- The derivative of the function f'(x) is as follows:

- The square of derivative of f(x) is:

- Now use the surface area formula:
![S = 2*\pi \int\limits^6_1 { [\sqrt{42x-x^2} *\sqrt{1 + \frac{(21-x)^2}{42x-x^2 } }] \, dx\\\\S = 2*\pi \int\limits^6_1 { [\sqrt{42x-x^2+(21-x)^2} }] \, dx\\\\S = 2*\pi \int\limits^6_1 { [\sqrt{42x-x^2+441-42x+x^2} }] \, dx\\\\S = 2*\pi \int\limits^6_1 { [\sqrt{441} }] \, dx\\S = 2*\pi \int\limits^6_1 { 21} \, dx\\\\S = 42*\pi \int\limits^6_1 { dx} \,\\\\S = 42*\pi [ 6 - 1 ]\\\\S = 42*5*\pi \\\\S = 210\pi](https://tex.z-dn.net/?f=S%20%3D%202%2A%5Cpi%20%5Cint%5Climits%5E6_1%20%7B%20%5B%5Csqrt%7B42x-x%5E2%7D%20%2A%5Csqrt%7B1%20%2B%20%5Cfrac%7B%2821-x%29%5E2%7D%7B42x-x%5E2%20%7D%20%7D%5D%20%5C%2C%20dx%5C%5C%5C%5CS%20%3D%202%2A%5Cpi%20%5Cint%5Climits%5E6_1%20%7B%20%5B%5Csqrt%7B42x-x%5E2%2B%2821-x%29%5E2%7D%20%7D%5D%20%5C%2C%20dx%5C%5C%5C%5CS%20%3D%202%2A%5Cpi%20%5Cint%5Climits%5E6_1%20%7B%20%5B%5Csqrt%7B42x-x%5E2%2B441-42x%2Bx%5E2%7D%20%7D%5D%20%5C%2C%20dx%5C%5C%5C%5CS%20%3D%202%2A%5Cpi%20%5Cint%5Climits%5E6_1%20%7B%20%5B%5Csqrt%7B441%7D%20%7D%5D%20%5C%2C%20dx%5C%5CS%20%3D%202%2A%5Cpi%20%5Cint%5Climits%5E6_1%20%7B%2021%7D%20%5C%2C%20dx%5C%5C%5C%5CS%20%3D%2042%2A%5Cpi%20%5Cint%5Climits%5E6_1%20%7B%20dx%7D%20%5C%2C%5C%5C%5C%5CS%20%3D%2042%2A%5Cpi%20%5B%206%20-%201%20%5D%5C%5C%5C%5CS%20%3D%2042%2A5%2A%5Cpi%20%5C%5C%5C%5CS%20%3D%20210%5Cpi)
- The Volume of the pain coating is:
V = S*t
V = 210*π*3/2000
V = 63π / 200 m^3
<u>Given </u><u>:</u><u>-</u>
- Length :- 8m
- Width :- 10
- Height :- 10m
<u>To </u><u>find</u><u> </u><u>:</u><u>-</u>
<u>Solution</u><u> </u><u>:</u><u>-</u>
formula for Surface Area = 2(LW + WH + HL)
- putting the known values,
Surface Area = 2(8×10 + 10×10 + 10×8) m²
<u>Surface</u><u> Area</u><u> </u><u>=</u><u> </u><u>2</u><u>(</u><u>2</u><u>6</u><u>0</u><u>)</u><u> </u><u>m²</u>
<u>Surface</u><u> Area</u><u> </u><u>=</u><u> </u><u>5</u><u>2</u><u>0</u><u>m</u><u>²</u><u> </u><u>(</u><u> </u><u>Option</u><u> </u><u>C</u><u>)</u>