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2 years ago

What is the surface of the prism?

Mathematics

1 answer:

jasenka [17]2 years ago

4 0

Given :-

Length :- 8m
Width :- 10
Height :- 10m

To find :-

Surface area

Solution :-

formula for Surface Area = 2(LW + WH + HL)

putting the known values,

Surface Area = 2(8×10 + 10×10 + 10×8) m²

Surface Area = 2(260) m²

Surface Area = 520m² ( Option C)

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The last time it placed an order for ingredients, Sweet Treats Bakery ordered 820 kilograms of sugar. This time, the bakery is o

d1i1m1o1n [39]

Answer:

Step-by-step explanation:

820 - 779 = 41. 41/820 = 0.05. 0.05 = 5%

7 0

3 years ago

Rob laid three sticks end to end. The lengths of the sticks were 45 millimeters, 32 centimeters, and 4 decimeters. How long, in

Oksanka [162]

Answer:

0.765 meters long were the sticks when laid end to end.

Step-by-step explanation:

Given:

Rob laid three sticks end to end. The lengths of the sticks were 45 millimeters, 32 centimeters, and 4 decimeters.

Now, to find the length in meters of the sticks when laid end to end.

The lengths of the sticks are:

1st stick - 45 millimeters.

2nd stick - 32 centimeters.

3rd stick - 4 decimeters.

So, we convert the units of sticks into meters by using conversion factor:

1st stick:

1 millimeter = 0.001 meter.

45 millimeters = 0.001 × 45

45 millimeters = 0.045 meter.

2nd stick:

1 centimeter = 0.01 meter.

32 centimeters = 0.01 × 32

32 centimeters = 0.32 meter.

3rd stick:

1 decimeter = 0.1 meter.

4 decimeters = 0.1 × 4

4 decimeters = 0.4 meter.

Now, adding all the three sticks length to get the the length in meters of the sticks when laid end to end:

$0.045+0.32+0.4\\\\=0.765\ meters.$

Therefore, 0.765 meters long were the sticks when laid end to end.

5 0

4 years ago

Rationalise the equation : <img src="https://tex.z-dn.net/?f=%20%5Cfrac%7By%20%5E%7B2%7D%20%7D%7B%20%5Csqrt%7Bx%5E%7B2%7D

Nat2105 [25]

Answer:

$\sqrt{x^2+y^2}-x$

Step-by-step explanation:

$\textsf{Mulitply by}\quad\dfrac{\sqrt{x^2+y^2}-x}{\sqrt{x^2+y^2}-x}:$

$\implies \dfrac{y^2}{\sqrt{x^2+y^2}+x} \times \dfrac{\sqrt{x^2+y^2}-x}{\sqrt{x^2+y^2}-x}$

$\implies \dfrac{y^2(\sqrt{x^2+y^2}-x)}{(\sqrt{x^2+y^2}+x)(\sqrt{x^2+y^2}-x)}$

$\implies \dfrac{y^2(\sqrt{x^2+y^2}-x)}{(\sqrt{x^2+y^2})^2-x^2}$

$\implies \dfrac{y^2(\sqrt{x^2+y^2}-x)}{x^2+y^2-x^2}$

$\implies \dfrac{y^2(\sqrt{x^2+y^2}-x)}{y^2}$

$\textsf{Cancel the common factor}\:y^2:$

$\implies \sqrt{x^2+y^2}-x$

6 0

3 years ago

Read 2 more answers

The distance from Earth to the sun, about 1.50 x 10^8 kilometers, is known as an astronomical unit. The nearest star, Proxima Ce

Anvisha [2.4K]

Answer:

Distance from Earth to Proxima Centauri (in scientific notation) = $3.9*10^{16}$ kilometers

Step-by-step explanation:

We need the conversion between Astronomical Unit and Kilometers.

The conversion is:

1 AU = 1.496*10^8 km

or rounded, given in this problem,

1 AU = $1.5*10^8$ km

We need the distance from Earth to Proxima Centauri:

$2.6*10^8$ AU * $1.5*10^8$ kilometers

When multiplying two numbers in scientific notation, we have to "multiply the coefficients" and "add the exponents".

Lets do this:

$(2.6*10^8)*(1.5*10^8)\\=(2.6*1.5)*10^{8+8}\\=3.9*10^{16}$

Distance from Earth to Proxima Centauri (in scientific notation) = $3.9*10^{16}$ kilometers

7 0

3 years ago

How would you use a number line to determine the sum of two negative numbers?

Bess [88]

Show me the problem

3 0

3 years ago