What is trouble shoot

Oxnard Casualty wants to ensure that their e-mail server has 99.98 percent reliability. They will use several independent server

sattari [20]

Answer:

The smallest number of servers required is 3 servers

Explanation:

Given

$Reliability = 99.98\%$

$Individual Servers = 95\%$

Required

Minimum number of servers needed

Let p represent the probability that a server is reliable and the probability that it wont be reliable be represented with q

Such that

$p = 95\%\\$

It should be noted that probabilities always add up to 1;

So,

$p + q = 1$ '

Subtract p from both sides

$p - p + q = 1 - p$

$q = 1 - p$

Substitute $p = 95\%\\$

$q = 1 - 95\%$

Convert % to fraction

$q = 1 - \frac{95}{100}$

Convert fraction to decimal

$q = 1 - 0.95$

$q = 0.05$

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To get an expression for one server

The probabilities of 1 servers having 99.98% reliability is as follows;

$p = 99.98\%$

Recall that probabilities always add up to 1;

So,

$p + q = 1$

Subtract q from both sides

$p + q - q = 1 - q$

$p = 1 - q$

So,

$p = 1 - q = 99.98\%$

$1 - q = 99.98\%$

Let the number of servers be represented with n

The above expression becomes

$1 - q^n = 99.98\%$

Convert percent to fraction

$1 - q^n = \frac{9998}{10000}$

Convert fraction to decimal

$1 - q^n = 0.9998$

Add $q^n$ to both sides

$1 - q^n + q^n= 0.9998 + q^n$

$1 = 0.9998 + q^n$

Subtract 0.9998 from both sides

$1 - 0.9998 = 0.9998 - 0.9998 + q^n$

$1 - 0.9998 = q^n$

$0.0002 = q^n$

Recall that $q = 0.05$

So, the expression becomes

$0.0002 = 0.05^n$

Take Log of both sides

$Log(0.0002) = Log(0.05^n)$

From laws of logarithm $Loga^b = bLoga$

So,

$Log(0.0002) = Log(0.05^n)$ becomes

$Log(0.0002) = nLog(0.05)$

Divide both sides by $Log0.05$

$\frac{Log(0.0002)}{Log(0.05)} = \frac{nLog(0.05)}{Log(0.05)}$

$\frac{Log(0.0002)}{Log(0.05)} = n$

$n = \frac{Log(0.0002)}{Log(0.05)}$

$n = \frac{-3.69897000434}{-1.30102999566}$

$n = 2.84310893421$

$n = 3 (Approximated)$

Hence, the smallest number of servers required is 3 servers

6 0

3 years ago

There exists a data type Date with member function Increment that increments the current Date object by one. The ++ operator is

nalin [4]

Answer:

Date Date::operator++( int )

{

Date temp = *this;

Increment();

return temp;

}

Explanation:

Of options 1 through 4, only option 4 correctly implement the post increment of the ++ operator.

Interpreting each line of option for and comparing it to other options

Line 1: Date Date::operator++( int )

This declares the data type and its ++ operator

This is same for all options

Line 2: The Date type needs to be declared

In option 4, it was declared correctly as Date temp = *this; using a pointer variable *this.

Here, option 2 is removed from the list of possible options.

Comparing other options

Line 3: The member increment option needs to be declared after the declaration of the date type variable.

This is correctly declared as Increment(); in option 4

Here, option 3 is removed from the list of possible options.

Comparing other options

Line 4: The value declared variable temp needs to be returned the way it was declared (without pointer indicator)

Hence, option 4 is best appropriate

3 0

3 years ago

Write a program that generates 1,000 random integers between 0 and 9 and displays the count for each number. (Hint: Use a list o

masya89 [10]

Answer:

import random

count0, count1, count2, count3,

count4, count5, count6, count7,

count8, count9, i = [0 for _ in range(11)]

while i < 1000:

number = random.randint(0,9)

if number == 0:

count0 = count0 + 1

if number == 1:

count1 = count1 + 1

if number == 2:

count2 = count2 + 1

if number == 3:

count3 = count3 + 1

if number == 4:

count4 = count4 + 1

if number == 0:

count5 = count5 + 1

if number == 6:

count6 = count6 + 1

if number == 7:

count7 = count7 + 1

if number == 0:

count8 = count8 + 1

if number == 9:

count9 = count9 + 1

i = i+1

print("0's: "+ str(count0) + "\n"+ "1's: "+ str(count1) + "\n"+

"2's: "+ str(count2) + "\n"+ "3's: "+ str(count3) + "\n"+

"4's: "+ str(count4) + "\n"+ "5's: "+ str(count5) + "\n"+

"6's: "+ str(count6) + "\n"+ "7's: "+ str(count7) + "\n"+

"8's: "+ str(count8) + "\n"+ "9's: "+ str(count9) + "\n")

Explanation:

- Initialize variables to hold the count for each number

- Initialize i to control the while loop

- Inside the while loop, check for the numbers and increment the count values when matched.

- Print the result

5 0

3 years ago

Which logic gate produces an output of 1 only if both its inputs are 0

Anettt [7]

0=false

1=true

false + false = true

0+0=1

+ operator = and function

AND GATE

8 0

3 years ago

Read 2 more answers

To pinpoint an earthquake's location, scientists need information from how many seismometers?

Mazyrski [523]

C. 3
Due to the different speeds of P and S waves, a single seismometers can determine the distance to an earthquake. So, for a single station, the localization is any point on a circle around the station. With 2 stations, you'll have two circles that intersect at two points. The 3rd station is needed in order to determine which of the 2 points is the actual earthquake.

7 0

3 years ago

What is trouble shoot​

What is trouble shoot