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Rudik [331]
3 years ago
7

I don't understand plz help​

Mathematics
2 answers:
Rasek [7]3 years ago
8 0

Answer:

The equation that represent x, the height of the sign is;

2a = 3x

Step-by-step explanation:

Given that the area of the triangular yield is A square feet

and it has a base length of 3 feet.

also the height is represented by x;

b = 3ft \\ h = x

Recall that the area of a triangle can be written as;

a =  \frac{1}{2} bh

substituting the given;

a =  \frac{1}{2}  \times 3 \times x \\   a =  \frac{3}{2} x \\ 2a = 3x

Therefore, the equation that represent x, the height of the sign is;

2a = 3x

fgiga [73]3 years ago
5 0
The answer to the question is 2A=3x
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Can you guys help with at least one of these two? Thanks!
Finger [1]

Answer:

1) B. -2 hours per person

2) C. 3.60 per pound

Step-by-step explanation:

1)

We can make a slope triangle connecting the points (4, 12) and (10,0)

We get -12/6, or -2 as our slope & final answer

2)

You can do x/y to find the unit rate for this one, or in this case 18/5 = 3.6

7 0
2 years ago
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frozen [14]

40 Butterflies at Swallowtail :D

7 0
3 years ago
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Lostsunrise [7]
35 cats (70%) 15 dogs (30%)

50 x 70% = 35

50 - 35 = 15 (remaining 30%)

1. Find the amount of cats.
2. There are 50 dogs and cats, 30% are dogs.
3. multiplication
4. Formula shown above

Hope this helps!
8 0
3 years ago
A farmer in China discovers a mammal hide that contains 37% of its original amount of C-14. Find the age of the mammal hide to t
Naya [18.7K]

Answer: 54678 years

Step-by-step explanation:

This can be solved by the following equation:

N_{t}=N_{o}e^{-\lambda t} (1)

Where:

N_{t}=54\%=0.54 is the quantity of atoms of carbon-14 left after time t

N_{o}=1 is the initial quantity of atoms of C-14 in the mammal hide

\lambda is the rate constant for carbon-14 radioactive decay

t is the time elapsed

On the other hand, \lambda has a relation with the half life h of the C-14, which is 5730 years:

\lambda=\frac{ln(2)}{h}=\frac{ln(2)}{5730 years}=1.21(10)^{-4} years^{-1}=0.000121 years^{-1} (2)

Substituting (2) in (1):

0.54=1e^{-(0.000121 years^{-1}) t} (3)

Applying natural logarithm on both sides of the equation:

ln(0.54)=ln(1e^{-(0.000121 years^{-1}) t}) (4)

-0.616=-(0.000121 years^{-1}) t (5)

Isolating t:

t=\frac{-0.616}{-0.000121 years^{-1}} (6)

t=54677.68 years \approx 54678 years (7)  This is the age of the mammal hide

8 0
3 years ago
Select all the situations that can be represented by 1/2⋅5. * 1 point Diego lives 5 miles from school, and Elena lives 1/2 as fa
SpyIntel [72]

Answer:

  • Elena lives 2.5 miles away from school.
  • The total liters of water is 2.5 liters
  • He can cut 10 pieces of rope of length 1/2 meter
  • The fraction of her goal she ran is 1/10

Step-by-step explanation:

From the question,

  • Diego lives 5 miles from school, and Elena lives 1/2 as far away as Diego

Therefore, Elena lives 1/2 of 5 miles away from school.

1/2 of 5 miles = 2.5 miles

Hence, Elena lives 2.5 miles away from school.

  • Jada has 5 bottles that each contain 1/2 liter of water.

Since each bottle contain 1/2 liter of water, then

The total liters of water is (1/2 × 5) liters

1/2 × 5 = 2.5 liters

Hence, the total liters of water is 2.5 liters

  • Noah has 5 meters of rope

To determine how many pieces of rope of length 1/2 meter he can cut,

Number of pieces of rope of length 1/2 meter that can be cut is 5 meter ÷ 1/2 meter

5 meter ÷ 1/2 meter = 10

Hence, he can cut 10 pieces of rope of length 1/2 meter.

  • Lin's goal is to run 5 miles. She ran 1/2 mile.

To determine what fraction of her goal that is,

First, she ran 1/2 mile out of 5 miles.

The fraction of her goal she ran is 1/2 mile ÷ 5 miles

1/2 mile ÷ 5 miles = 1/10

Hence, the fraction of her goal she ran is 1/10.

8 0
4 years ago
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