
$=(a^2-10a)-(b^2+6b) +16$
$=[(a^2-2(5)a+25)-25]-[(b^2+2(3)b+9)-9]+16$
$=(a-5)^2-25-(b+3)^2+9+16$
$=(a-5)^2-(b+3)^2$
Philip equation
ordered data: 3o(oranges), 3g(green), 6y, 8r, 13b(black, 15b(blue
mean: 8 mode: 3 range: 12
Answer:
w = 2
Step-by-step explanation:
2(4w - 1) = -10(w - 3) + 4
8w - 2 = -10w + 30 + 4
8w - 2 = -10w + 34
+10w +10w
18w - 2 = 34
+2 +2
<u>18w</u> = <u>36</u>
18 18
w = 2