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Drupady [299]
3 years ago
10

Which equation has no solution

Mathematics
2 answers:
jolli1 [7]3 years ago
8 0

answer : |4x-2| = -6

Absolute value is the distance of x from 0

The solution of absolute value cannot be negative

Distance is always positive. So solution of absolute value cannot be negative.

|4x-2| = -6

The distance cannot be -6. So there is no solute for this equation.

The other equations have only positive value or 0 on the right side. so other three absolute equation can be solved.

so |4x-2| = -6 has no solution

kaheart [24]3 years ago
6 0

Answer:

|4x-2|=-6

Step-by-step explanation:

 1. By definition, an absolute value is always expressed as a positive number or zero.

2. Based on the information shown above, when you have an equation as the equation of the first option ( |4x-2|=-6), you can conclude that this equation has no solution, because it is impossible to have an absolute value equal to -6.

3. Therefore, as you can see, the answer is the first option:  |4x-2|=-6.


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user100 [1]

Answer:

12x^2+8x+25

Step-by-step explanation:

Given

From Figure

Sides of Triangle

8x^2 \\4x^2+15\\8x+10

Now, using concept

Perimeter of triangle = Sum of the sides of triangle

So,

Perimeter of triangle = 8x^2+4x^2+15+8x+10

Adding 8x^2 and 4x^2, so,

Perimeter of triangle = 12x^2+15+8x+10

This can be written as

Perimeter of triangle = 12x^2+15+8x+10

Adding 15 and 10,

Perimeter of triangle = 12x^2+8x+25

So, the correct choice is = 12x^2+8x+25

Hope this helps.

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3 years ago
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3 years ago
The length of a rectangle is 5 units more than the width. The area of the rectangle is 36 units. What is the width, in units, of
PIT_PIT [208]

Answer:

4

Step-by-step explanation:

Let y be the width of the rectangle

The length of the rectangle is 5 unit more than the width. This is written as:

Length = y + 5

Area = 36

Recall:

Area of rectangle = length x width

36 = (y + 5) x y

36 = y^2 + 5y

Rearrange the expression

y^2 + 5y — 36 = 0

To solve this problem by factorization, multiply the first term (i.e y^2) and last term ( i.e — 36) together. This gives — 36y^2

Next, find two factors of —36y^2 such that when we add them together it will result to the second term (5y). These factors are —4y and 9y. Now we substitute —4y and 9y in place of 5y in the equation. This is illustrated below:

y^2 + 5y — 36 = 0

y^2 —4y + 9y — 36 = 0

We factorize as follows:

y(y — 4) + 9(y —4) = 0

(y + 9) (y — 4) =0

y + 9 = 0 or y — 4 = 0

y = —9 or y = 4

Since the measurement can not be negative, therefore y (i.e the width) is 4

4 0
3 years ago
The mean of the temperatures in the chart is 24° with a standard deviation of 4°. Which temperature is within one standard devia
VARVARA [1.3K]

Answer:

22°

Step-by-step explanation:

If the mean is m and the standard deviation is s, then we can say that the temperatures that fall <em><u>within 1 standard deviation of the mean</u></em> will be:

m - s < temperatures < m + s

To we take the sum of mean and standard deviation: 24 + 4 = 28

and, the different of mean and standard deviation: 24 - 4 = 20

So, <em>the temperature that is in between 20 and 28 is the temperature within 1 standard deviation of the mean</em>.

This is the third answer, 22°

5 0
3 years ago
Read 2 more answers
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