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Snezhnost [94]
2 years ago
15

An expression is shown. 4.8 x 2 + 3.2, what is the value of the expression?

Mathematics
2 answers:
dimaraw [331]2 years ago
7 0

Answer:

12.8

Step-by-step explanation:

follow the steps: parenthesis, exponents, multiplication/division, addition/subraction

so, since multiplication comes before addition, you are going to do 4.8 x 2 before adding 3.2

4.8 x 2=9.6

9.6+3.2=12.8

madreJ [45]2 years ago
3 0
Answer is 23
Explanation is that 4.8 equals 11.5 in trigenomes, so 11.5 times 2 is 23. Happy to help :)
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dybincka [34]

Step-by-step explanation:

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7 0
3 years ago
Represent this statement as an equation: The product of a number and 4 plus 2 is 14.
DiKsa [7]

Answer:

4x+2=14

Step-by-step explanation:

8 0
3 years ago
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Answer:

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Step-by-step explanation:

I'm not sure if it's right but you can try it

6 0
3 years ago
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How do you do this question?
alina1380 [7]

Answer:

(8√2) / 15

Step-by-step explanation:

A curve bounded by the y-axis is represented by in terms of dy;

\int \:x\:dt

When the curve crosses the y-axis, x will be 0. In this case x is the function of t, so we have to solve for x(t) = 0;

0 = t^2 + 2t --- (1)

Solution(s) => t = 0, t = 2

dy = (1/2 * 1/√t)dt --- (2)

Our solutions (0, 2) are our limits. The area of the curve is in the form A\:=\:\int _b^a\:f\left(t\right)g'\left(t\right)dt , so now let's introduce the limits of integration, x(t) and dy/dt. Remember, dy/dt = (1/2 * 1/√t) (second equation). 1/2 * 1/√t can be rewritten as 1/2 * t^(-1/2)....

A\:=\:\int _2^0\:\left(t^2-2t\right)\left(\frac{1}{2}t^{-\frac{1}{2}}\right)dt\\\\= \int _2^0\:\left(\frac{1}{2}t^{\frac{3}{2}}-t^{\frac{1}{2}}\right)dt\\\\= \left[\frac{t^{\frac{5}{2}}}{5}-\frac{2t^{\frac{3}{2}}}{3}\right]_2^0\\\\= 0\:-\:\left(\frac{4\sqrt{2}}{5}-\frac{4\sqrt{2}}{3}\right)\\\\= \frac{8\sqrt{2}}{15}

Your solution is 8√2 / 15

7 0
2 years ago
Question 1 (15 points)
marta [7]

Answer:

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Step-by-step explanation:

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2 years ago
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