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3 years ago

Caroline has 16 marbles 1/8 of them are blue how many of Caroline's marbles are blue

2 answers:

5 0

Here's another way; You divide 1 by 8, because 1/8 is equal to 1 ÷ 8, and 1 ÷ 8 is equal to (0.125). So if you multiply 1.25 by 16 you'll get 2. Hope this way helps, if you're confused I don't blame you. xD

DedPeter [7]3 years ago

4 0

2 . You have to divide 16 by 8. you get 2 . Hoped that helped

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What is the slope of a line that is perpendicular to the line whose equation is 8y−5x=11?

ElenaW [278]

9514 1404 393

Answer:

-8/5

Step-by-step explanation:

When you solve for y, the slope of the line is the x-coefficient. For the given line, that is ...

8y = 5x +11 . . . . . add 5x

y = 5/8x +11/8 . . . . divide by 8

The given line has a slope of 5/8. The perpendicular line will have a slope that is the opposite of the reciprocal of this:

-1/(5/8) = -8/5 . . . . slope of perpendicular line

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3 years ago

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meriva

Answer:

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3 years ago

Someone pls help it’s for my exams

Anna35 [415]

Answer:

Step-by-step explanation:

you know that both angles=180

6x+20+2x+4=180

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3 years ago

H+12.5=-12.5 what does h equal?

valentinak56 [21]

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lim x rightarrow 0 1 - cos ( x2 ) / 1 - cosx The limit has to be evaluated without using l'Hospital'sRule.

zaharov [31]

Answer with Step-by-step explanation:

Given

$f(x)=\frac{1-cos(2x)}{1-cos(x)}\\\\\lim_{x \rightarrow 0}f(x)=\lim_{x\rightarrow 0}(\frac{1-(cos^2{x}-sin^2{x})}{1-cos(x)})\\\\(\because cos(2x)=cos^2x-sin^2x)\\\\\lim_{x \rightarrow 0}f(x)=\lim_{x\rightarrow 0}(\frac{1-cos^2x}{1-cos(x)}+\frac{sin^2x}{1-cosx})\\\\=\lim_{x\rightarrow 0}(\frac{(1-cosx)(1+cosx)}{1-cosx}+\frac{sin^2x}{1-cosx})\\\\=\lim_{x\rightarrow 0}((1+cosx)+\frac{sin^2x}{1-cosx})\\\\\therefore \lim_{x \rightarrow 0}f(x)=1$

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