Answer:
Step-by-step explanation:
We are given the following information in the question:

where a > 0 and b > 0.


where v(t) is the required tumor volume as a function of time that has an initial tumor volume of V(0) = 1 cubic mm.
Answer: A.56 sq. units
Step-by-step explanation:
A=( a+b)h/2
(12+16)4/2
(28)2
56
A=56
Answer:
7 units
Step-by-step explanation:
Answer:
∠ HGL = 73°
Step-by-step explanation:
KL is a midsegment of the triangle and is parallel to HG, then
∠ KLJ = ∠ HGL ( corresponding angles ), so
9x - 62 = 5x - 2 ( subtract 5x from both sides )
4x - 62 = - 2 ( add 62 to both sides )
4x = 60 ( divide both sides by 4 )
x = 15
Thus
∠ HGL = 5x - 2 = 5(15) - 2 = 75 - 2 = 73°