Answer:
–0.83
Step-by-step explanation:
An r-value, or correlation coefficient, tells us the strength of the correlation in a linear regression. This number ranges from -1 to 1; -1 is a perfect linear fit for a decreasing set of data, while 1 is a perfect linear fit for an increasing set of data.
The closer the r-value is to either -1 or 1, the stronger the correlation is.
The two negative numbers we have are -0.83 and -0.67. The first one, -0.83, is 0.17 away from -1. -0.67, on the other hand, is 0.33 away from -1. The two positive numbers we have are 0.48 and 0.79. The first one, 0.48, is 0.52 away from 1. The second one, 0.79, is 0.21 away from 1. The one that is closest to the perfect fit is -0.83, since it is only 0.17 away from a perfect fit.
Answer:
m∠C = 66°
Step-by-step explanation:
Since AB = BD, it means this triangle is an Isosceles triangle and as such;
∠BAD = ∠BDA = 24°
Thus, since sum of angles in a triangle is 180,then;
∠ABD = 180 - (24 + 24)
∠ABD = 180 - 48
∠ABD = 132°
We are told that BC = BD.
Thus, ∆BDC is an Isosceles triangle whereby ∠BCD = ∠BDC
Now, in triangles, we know that an exterior angle is equal to the sum of two opposite interior angles.
Thus;
132 = ∠BCD + ∠BDC
Since ∠BCD = ∠BDC, then
∠BCD = ∠BDC = 132/2
∠BCD = ∠BDC = 66°
Answer:
x²/2166784 +y²/2159989 = 1
Step-by-step explanation:
The relationship between the semi-axes and the eccentricity of an ellipse is ...
e = √(1 -b²/a²)
In order to write the desired equation we need to find 'b' from 'e' and 'a'.
__
<h3>semi-minor axis</h3>
Squaring the equation for eccentricity gives ...
e² = 1 -b²/a²
Solving for b², we have ...
b²/a² = 1 -e²
b² = a²(1 -e²)
<h3>ellipse equation</h3>
Using the given values, we find ...
b² = 1472²(1 -0.056²) = 2166784(0.996864) ≈ 2159989
The desired equation is ...
x²/2166784 +y²/2159989 = 1
