Add
5
5
to both sides of the equation.
√
2
x
+
13
=
x
+
5
2
x
+
13
=
x
+
5
To remove the radical on the left side of the equation, square both sides of the equation.
(
√
2
x
+
13
)
2
=
(
x
+
5
)
2
(
2
x
+
13
)
2
=
(
x
+
5
)
2
Simplify each side of the equation.
2
x
+
13
=
x
2
+
10
x
+
25
2
x
+
13
=
x
2
+
10
x
+
25
Solve for
x
x
.
x
=
−
2
,
−
6
x
=
-
2
,
-
6
Exclude the solutions that do not make
√
2
x
+
13
−
5
=
x
2
x
+
13
-
5
=
x
true.
x
=
−
2
Answer:
Step-by-step explanation:
J is a tangent to the circle and it is at right angle,
So applying Pythagorean theorem
HK² = KJ² + HJ²
HK² = 8²+ 15²
HK² = 64 + 225
HK² = 289
HK = √289
HK = 17 mi
Answer:
2
Step-by-step explanation:
Answer:
3x^3 + 3x^2 - 27x - 27
Step-by-step explanation:
Answer:
60
Step-by-step explanation:
1. Substitute
8 (10) - 20
2. Multiply
80 - 20
3. Subtract
60
