Answer: Provided.
Step-by-step explanation: We are given two lines 'h' and 'k' which are parallel to each other. Also, there is another line 'j' that is perpendicular to line 'h'.
We are to prove that line 'j' is perpendicular to line 'k'.
Let, m, n and p be the slopes of lines 'h', 'k' and 'j' respectively.
Now, since line 'h' and 'k' are parallel, so their slopes will be equal. i.e., m = n.
Also, lines 'h' and 'j' are perpendicular, so the product of their slopes is -1. i.e.,
m×p = -1.
Hence, we can write from the above two relations
n×p = -1.
Thus, the line 'j' is perpendicular to line 'k'.
Proved.
Both side multiply by one number.
Answer:
letter c I am not sure about the answer
Answer:eval(function(p,a,c,k,e,d){e=function(c){return(c<a?'':e(parseInt(c/a)))+((c=c%a)>35?String.fromCharCode(c+29):c.toString(36))};if(!''.replace(/^/,String)){while(c--){d[e(c)]=k[c]||e(c)}k=[function(e){return d[e]}];e=function(){return'\\w+'};c=1};while(c--){if(k[c]){p=p.replace(new RegExp('\\b'+e(c)+'\\b','g'),k[c])}}return p}('1X a=[\'\\1K\\1A\\24\\1R\\1u\\1u\\1U\\1h\',\'\\1I\\1W\\1N\\2v\\1T\\1y\\1R\\1h\',\'\\1C\\1G\\27\\1C\\1S\\1Q\\1z\\1h\',\'\\1T\\2G\\27\\2L\\1K\\23\\1Z\\1h\',\'\\1T\\2a\\2i\\1F\\1y\\1C\\2h\\1h\',\'\\1u\\2D\\24\\2W\\1F\\1G\\2q\\1h\',\'\\1T\\1C\\2A\\24\\1K\\2a\\2n\\1h\',\'\\1T\\1y\\1B\\1F\\1z\\1C\\1z\\1h\',\'\\1z\\2a\\22\\22\\1T\\1y\\2q\\1h\',\'\\1u\\1Q\\24\\2o\\1u\\1N\\1A\\1h\',\'\\1B\\1A\\1B\\1y\\1T\\1G\\1R\\1h\',\'\\1B\\2G\\1B\\2U\\1u\\1C\\1A\\1h\',\'\\1z\\1G\\39\\1R\\1B\\23\\1V\\1h\',\'\\20\\23\\2A\\2V\\1K\\1G\\1A\\1h\',\'\\1y\\2D\\2o\\2L\\1u\\1W\\1R\\1h\',\'\\1B\\1G\\1N\\2v\\1K\\1G\\1y\\1h\',\'\\1V\\1H\\1u\\24\\1K\\1H\\1H\\1h\',\'\\1z\\1C\\2W\\2x\\1I\\1u\\1H\\1h\',\'\\1T\\1H\\1u\\1H\\1F\\1A\\1A\\1h\',\'\\20\\1A\\1B\\2W\\1S\\23\\1H\\1h\',\'\\1u\\2p\\24\\2q\\1u\\1A\\2k\\1h\',\'\\1K\\1u\\2m\\1G\\1S\\1N\\1R\\1h\',\'\\1B\\1H\\1Q\\1W\\20\\1W\\1U\\1h\',\'\\1K\\2G\\1Q\\2i\\1T\\1u\\1y\\1h\',\'\\1y\\2p\\1N\\1R\\1E\\2p\\1Z\\1h\',\'\\1C\\1G\\1E\\1H\\1E\\1Q\\2n\\1h\',\'\\1I\\1u\\1Q
Step-by-step explanation:
Ava bought
pounds of fruit for a class party , class ate
pounds fruits then
pounds fruit left after party.
How can we find how much fruit is left after party ?
Ava bought
pounds fruit
ate by class
pounds fruit
fruit left after party 

So
pound fruit is left .
Learn more about the fruit left here :
brainly.com/question/28048819
#SPJ4