∫ e^(3x)*(cosh(2x)dx
= ∫ [e^(3x)*(e^(2x)+e^(-2x))/2]dx
= ∫ [(e^(5x)+e^x)/2]dx
=e^(5x)/10+e^x/2+C
=(1/10)(e^(5x)+5e^x)+C
2009 - 1894 = 115
That appears to be the same number as
the one that appears in Choice-'B'.
Answer:
-3x^2
Step-by-step explanation:
Answer:
The precision is determined by the POSITION of the number 6 - NOT its value.
