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iren2701 [21]
3 years ago
14

Consider functions f and g.

Mathematics
2 answers:
abruzzese [7]3 years ago
7 0

Answer:

letter c I am not sure about the answer

KatRina [158]3 years ago
7 0

Answer:

The answer would be A

Step-by-step explanation:

You have to combine all of the like terms and 7x^4 has no other like term since its to the power of 4

9x^3 and 11x^3 both have the power of 3 so you multiply them together to get 99x^3 then 3x^2 doesn't have a like term so it stays as 3x^2

Which gets you the answer of 7x^4+99x^3-3x^2

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If f(x)=2x^2sqrt(x-2), complete the following statement f(6)
aliina [53]
F(6) means that for every value of x in the function, you plug in a 6. So, 
f(6) = 2(6)^2 + 5*sqrt((6) - 2)

This equals 82.
7 0
3 years ago
Read 2 more answers
According to a candy​ company, packages of a certain candy contain 1616​% orange candies. Suppose we examine 100100 random candi
GaryK [48]

Answer:

a) By the Central Limit Theorem, 16%.

b) 0.0367 = 3.67%

c) We expect 16% orange​ candies, give or take 3.67%.

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For samples of size n of a proportion p, the expected sample percentage is p and the standard error is s = \sqrt{\frac{p(1-p)}{n}}

In this problem, we have that:

p = 0.16, n = 100

a. What value should we expect for our sample percentage of orange​ candies?

By the Central Limit Theorem, 16%.

b. What is the standard​ error?

s = \sqrt{\frac{0.16*0.84}{100}} = 0.0367

0.0367 = 3.67%

c. Use your answers to fill in the blanks below. We expect​ ____% orange​ candies, give or take​ _____%.

We expect 16% orange​ candies, give or take 3.67%.

3 0
2 years ago
Find an explicit rule for the nth term of the sequence. <br><br> 2, -8, 32, -128, ...
Akimi4 [234]
A1=2
a2=-8
a3=32
a4=-128

a2/a1=(-8)/2→a2/a1=-4
a3/a2=32/(-8)→a3/a2=-4
a4/a3=(-128)/32→a4/a3=-4

a2/a1=a3/a2=a4/a3=r=-4

an=a1*r^(n-1)
an=2*(-4)^(n-1)

The explicit rule for the nth term of the given sequence is an=2*(-4)^(n-1) 
8 0
3 years ago
A pair of dice is rolled. Find the probability for P(not 2 or not 12)
irakobra [83]

Answer:

There’s only one way to get 12 when 2 dice are tossed, both have to equal 6. There are 6 ways tossing a single die can come out (1,2,3,4,5,6), so if you toss dice, the second die could have any one of six values with each of the numbers that could result from the first toss (e.g., 1 from die 1 and 1,2,3,4,5, or 6 from die 2). So, considering there are 6 ways to fill each of two slots, there are 6 x 6 = 36 possible outcomes of tossing two dice. Only one of them equals 12, so p(12 given 2 dice tossed) = 1/36 = 0.02777777777778.

3 0
2 years ago
Match each power of a power expression with its simplified expression.
VARVARA [1.3K]

Answer:

> (4^6)^{-3} = \frac{1}{4 ^ {18}}

> (4^{-3})^{-3} = 4 ^ 9

> (4^0)^{-9} = 4 ^0

> (-4^{-9})^2 = (-4) ^ {-18}

Step-by-step explanation:

We have to expand the powers of each of them:

> (4^6)^{-3} = 4^{(6 * -3)}

          = 4 ^ {-18}

(4^6)^{-3} = \frac{1}{4 ^ {18}}

> (4^{-3})^{-3} = 4 ^ {(-3 * -3)}

  (4^{-3})^{-3} = 4 ^ 9

> (4^0)^{-9} = 4 ^ {(0 * -9)}

  (4^0)^{-9} = 4 ^0

> (-4^{-9})^2 = -4 ^ {( -9 * 2)}

  (-4^{-9})^2 = -4 ^ {-18}

8 0
2 years ago
Read 2 more answers
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