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4 years ago

What is the equation in point form of the line that passes through the point (2,6) and has a slope of 2

Mathematics

1 answer:

andriy [413]4 years ago

4 0

point slope form

y-y1 = m(x-x1)

y-6 = 2(x-2)

from the answers shown, should the slope be 5?

then the answer would be

y-6 = 5(x-2)

Choice A

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What percent of 48 is 54

lisov135 [29]

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Answer: 54 is 112.5% of 48.

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3 years ago

Which of the following is NOT possible? A = A triangle where one angle measures 20 degrees and another angle measures 45 degrees

ArbitrLikvidat [17]

Answer:

Step-by-step explanation:

the angle measures of triangles must add up to 180 degrees. Since we are only given two angles, we can assume that all of the answers that add up to be below 180 degrees fulfill this requirement with the third angle. However, answer choice C adds up to 190 degrees on the first two angle, which means that no matter how low the third angle is, it will never add up to 180 degrees.

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3 years ago

If 25 worker need 3 days to build a house how long will 10 worker need

Dmitrij [34]

Answer:

3 x 10 = 30 man-days per house

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3 years ago

Read 2 more answers

Can someone help me please id really appreciate it , i’ll give you brainliest

ozzi

Answer:

Alternate Exterior Angles Theorem

Step-by-step explanation:

By looking, we can see that they are exterior angles. Because 2 parallel lines are cut by a transversal, the angles are congruent.

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3 years ago

Consider randomly selecting a student at a large university. Let A be the event that the selected student has a Visa card, let B

Tems11 [23]

Answer:

0.75

Step-by-step explanation:

Given,

P(A) = 0.6, P(B) = 0.4, P(C) = 0.2,

P(A ∩ B) = 0.3, P(A ∩ C) = 0.12, P(B ∩ C) = 0.1 and P(A ∩ B ∩ C) = 0.07,

Where,

A = event that the selected student has a Visa card,

B = event that the selected student has a MasterCard,

C = event that the selected student has an American Express card,

We know that,

P(A ∪ B ∪ C) = P(A) + P(B) + P(C) - P(A ∩ B) - P(A ∩ C) - P(B ∩ C) + P(A ∩ B ∩ C)

= 0.6 + 0.4 + 0.2 - 0.3 - 0.12 - 0.1 + 0.07

= 0.75

Hence, the probability that the selected student has at least one of the three types of cards is 0.75.

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3 years ago