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Ganezh [65]
3 years ago
14

Complete the two column proof Given: 22= 24,m_2 = 110°

Mathematics
1 answer:
Savatey [412]3 years ago
6 0

Step-by-step explanation:

I took 3 indicated as 5 and its adjacent angle to be 3

<2 = <4

As <2 =<3( corresponding angle)

And <3 = <4 ( Vertically opp.angle)

hence <2 = <4

<2 =>110

so , <4 = 110

So, <4 =>110

As <4 and <5 form linear pair

So <4 + <5 =>180

<5 = 180 -110 =>70

As i took <5 as replacing angle to <3

So According to Question fig

<3 =>70

Hence proved

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zimovet [89]
<h3>Answer:  70.9%</h3>

Work Shown:

56/79 = 0.70886 approximately

Move the decimal point 2 spots to the right to go from 0.70886 to 70.886%

That rounds to 70.9%

3 0
2 years ago
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The probability of pulling out a bag of colored marbles is 2:5. If you were to pull colored marbles out of the bag one at a time
olchik [2.2K]

THIS IS THE COMPLETE QUESTION BELOW;

The probability of pulling a green marble out of a bag of colored marbles is 2:5. If you were to pull colored marbles out of the bag one at a time, and putting the marble back each time for 600 tries, approximately how many time would you select a green marble?? ( explanation too) 7th grade Math

Answer:

We would approximately pick a green marble 240 times

Step-by-step explanation:

Given from the question the probability of pulling a green marble out of a bag of colored marbles is 2:5

Let us denote the number of trials as X

Now the approximately number of times a green marble can be selected would be

=2/5 times

From the question we are given 600 trials

which implies our x=600

Therefore, the number of times we would pick a green marble is:

2/5 × 600 times

≈ 240 times

Therefore, we would approximately pick a green marble 240 times

4 0
3 years ago
Find the cardinality of the following set. A = { 12 , 14 , 16 , 18 , 20 }
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Answer:

2

Step-by-step explanation:

Because they are using the number line: 2, 4, 6, 8, 10, 12, 14, 16, 18, 20

6 0
2 years ago
Triangle abc is similar to triangle def solve for both unknown sides
Serhud [2]

Given:

Triangles ABC and DEF are similar triangles.

AB = 6 m, BC = 16 m, CA = 15 m, DE = x, EF = 32 m, FD = y

To find:

The values of unknown sides, i.e., x and y.

Solution:

We know that the corresponding parts of similar triangles are proportional and triangles ABC and DEF are similar triangles, so

\dfrac{AB}{DE}=\dfrac{BC}{EF}=\dfrac{CA}{FD}

\dfrac{6}{x}=\dfrac{16}{32}=\dfrac{15}{y}

\dfrac{6}{x}=\dfrac{1}{2}=\dfrac{15}{y}

Now,

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6\times 2=1\times x

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Similarly,

\dfrac{1}{2}=\dfrac{15}{y}

1\times y=15\times 2

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Therefore, the measure of unknown sides are x = 12 m and y = 30 m.

7 0
2 years ago
Find the exact length of the third side
VMariaS [17]

Answer:

2 root 15

Step-by-step explanation:

2 squared + x squared= 8 squared

4+ x squared= 64

xsquared =60

square root of sixty = 2 root 15

3 0
3 years ago
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