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kenny6666 [7]
3 years ago
15

A car initially moving at 9 m/s begins accelerating at its maximum acceleration of 4 m/s2. if the car maintains this acceleratio

n, how much time will it take to cover 200 m?

Physics
1 answer:
umka21 [38]3 years ago
4 0
The answer is in attachment.

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If a car with a mass of 1,200 kg traveling westward at 30 m/s is
forsale [732]

The net force acting on the car is equal to -12000 Newton.

<u>Given the following data:</u>

  • Mass = 1,200 kg
  • Initial velocity = 30 m/s.
  • Final velocity = 0 m/s (since the car came to a stop).
  • Time = 3 seconds.

To determine the net force acting on the car:

<h3>How to calculate the net force.</h3>

Mathematically, the net force acting on the car is given by Newton's Second Law of Motion:

F = \frac{m(v\;-\;u)}{t}

<u>Where:</u>

  • m is the mass.
  • t is the time.
  • u is the initial velocity.
  • u is the final velocity.

Substituting the given parameters into the formula, we have;

F = \frac{1200 \times (0\;-\;30)}{3}\\\\F = \frac{1200 \times (-30)}{3}\\\\F = \frac{-36000 }{3}

Net force = -12000 Newton.

Read more on net force here: brainly.com/question/1121817

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2 years ago
What is a safety precaution that should be taken when measuring the volume of an irregular object?
Goshia [24]

Answer:

The spillage of water

<em>PRECAUTION</em><em>:</em> Keep eureka can away from table edges and collect the displaced water in a measuring cylinder

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3 years ago
A force which resist the relative motion of two bodies in direct contact is called _______
Elena-2011 [213]

Frictional Force is the answer..

Hope it helps

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4 years ago
A crash test dummy with a mass of 55kg is placed into a car traveling at 40m/s. During the first trial the dummy does not wear a
s2008m [1.1K]

a. The force experienced by the dummy with a seatbelt is 11,000 Newton.

b. The force experienced by the dummy without a seatbelt is 4,400 Newton.

<u>Given the following data:</u>

  • Mass = 55 kg
  • Initial velocity = 0 m/s
  • Final velocity = 40 m/s
  • Time A = 0.2 seconds
  • Time B = 0.5 seconds

a. To calculate the force experienced by the dummy with a seatbelt:

<h3>Newton's Second Law of Motion</h3>

In order to solve for the force acting on the dummy, we would apply Newton's Second Law of Motion.

<u>Note:</u> The acceleration of an object is equal to the rate of change in velocity with respect to time.

Mathematically, Newton's Second Law of Motion is given by this formula;

F = \frac{M(v\;-\;u)}{t}

Substituting the given parameters into the formula, we have;

F = \frac{55(40\;-\;0)}{0.2}\\\\F = \frac{55\times 40}{0.2}\\\\F = \frac{2200}{0.2}

Force = 11,000 Newton.

b. To calculate the force experienced by the dummy without a seatbelt:

F = \frac{55(40\;-\;0)}{0.5}\\\\F = \frac{55\times 40}{0.5}\\\\F = \frac{2200}{0.5}

Force = 4,400 Newton.

Read more on force here: brainly.com/question/1121817

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3 years ago
Can someone help me with this? (Also C is incorrect)
Lena [83]

Answer:

i think its d

Explanation:

3 0
3 years ago
Read 2 more answers
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