Ask question

Ask question

All categories

3 years ago

15

A car initially moving at 9 m/s begins accelerating at its maximum acceleration of 4 m/s2. if the car maintains this acceleratio

n, how much time will it take to cover 200 m?

1 answer:

umka21 [38]3 years ago

4 0

The answer is in attachment.

You might be interested in

A straight bar magnet is initially 4 cm long, with the north pole on the right and the south pole on the left. if you cut the ma

Greeley [361]

The right half will be a new bar magnet of 2cm with north pole on the right side and south pole on teh left.

6 0

3 years ago

A cyclist accelerates from 0m/s to 8m/s in 3 seconds.

garik1379 [7]

Answer:

the rate of acceleration is 2.6666(and so on) if thats your question

Explanation:

5 0

3 years ago

A rocket is launched at an angle of = 49° above the horizontal with an initial speed vi = 54 m/s, as shown below. It moves for 2

4vir4ik [10]

I never seem to pretty best friends

7 0

3 years ago

The brakes on a bicycle apply 95 N of force to the wheels. When the

Veronika [31]

Answer:

idk

Explanation:

idk

6 0

3 years ago

Using energy considerations, calculate the average force (in N) a 67.0 kg sprinter exerts backward on the track to accelerate fr

Illusion [34]

Answer:

$F_{sprinter}=110.4N$

Explanation:

Given data

Mass m=67.0 kg

Final Speed vf=8.00 m/s

Initial Speed vi=2.00 m/s

Distance d=25.0 m

Force F=30.0 N

From work-energy theorem we know that the work done equals the change in kinetic energy

W=ΔK=Kf-Ki=1/2mvf²-1/2mvi²

And

$W=F_{total}.d$

So

$W=1/2mv_{f}^2-1/2mv_{i}^2\\F_{total}=\frac{1/2mv_{f}^2-1/2mv_{i}^2}{d} \\F_{total}=\frac{1/2(67.0kg)(8.00m/s)^2-1/2(67.0kg)(2.00m/s)^2}{25.0m} \\F_{total}=80.4N$

and we know that the force the sprinter exerted Fsprinter the force of the headwind Fwind=30.0N

So

$F_{sprinter}=F_{total}+F_{wind}\\F_{sprinter}=80.4N+30N\\F_{sprinter}=110.4N$

7 0

3 years ago

Read 2 more answers