GPE=mgh, where m=mass, g=acceleration due to gravity, h=height
We have a force of 675N already, so mg=675N
<span>GPE=mgh=675(26000)=17.55x10^6J</span>
Answer:
<em>The force exerted by each string is 25 N</em>
Explanation:
<u>Net Force</u>
The net force is the vector sum of forces acting on a body. The net force is a single force that represents the effect of the original forces on the body's motion. It gives the particle the same acceleration as all those actual forces together as described by Newton's second law of motion.
The picture described in the problem is hanging at rest supported by two vertical strings. This means that the net force acting on it is zero.
Assume the magnitude of each of these equal forces is F, and the picture has a weight of W=50 N, thus the net force is:
F + F - W
The positive signs indicate an upwards direction and the negative sign means a downwards direction. Since the net force is zero:
F + F - W = 0
2F = W
F = W/2 = 50 N/2
F = 25 N
The force exerted by each string is 25 N
I don’t rly get ur question
(a) 0.714 cm
First of all, we need to find the spring constant of the spring. This can be done by using Hooke's law:
where
F is the force applied on the spring
k is the spring constant
x is the stretching of the spring
At the beginning, the force applied is the weight of the block of m = 4.20 kg hanging on the spring, therefore:
The stretching of the spring due to this force is
x = 2.00 cm = 0.02 m
Therefore, the spring constant is
Now, a new object of 1.50 kg is hanging on the spring instead of the previous one. So, the weight of this object is
And so, the stretching of th spring in this case is
(b) 1.65 J
The work done on a spring is given by:
where
k is the spring constant
x is the stretching of the spring
In this situation,
k = 2060 N/m
x = 4.00 cm = 0.04 m is the stretching due to the external agent
So, the work done is
Use the formula pe=mgh to answer the height <span />
