Answer:
2.8 seconds
Explanation: Given that a simple pendulum that consists of a massless 2.00-meter length of rope attached to a 5.00-kg mass at one end. What is the period of oscillation for this simple pendulum
The parameters given are :
Length = 2 m
Mass = 5kg
Using the formula below
T = 2 pi × sqrt ( L / g )
Substitute all the parameters into the formula.
T = 2 × 3.143 × sqrt ( 2 / 9.8 )
T = 2 × 3.143 × 0.4517
T = 2.838 s
Therefore, the period of oscillation for this simple pendulum is 2.8 s approximately.
