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strojnjashka [21]
3 years ago
14

What is the potential energy of a ball that weighs 3kg and is at a height of 3m from the ground?

Physics
2 answers:
Savatey [412]3 years ago
8 0

Answer:

88.2 J (I put 10kg instead of 3kg last time oops)

Explanation:

https://www.calculatorsoup.com/calculators/physics/gravitational-potential.php

Eduardwww [97]3 years ago
7 0

Answer:

\boxed {\boxed {\sf 88.2 \ Joules}}

Explanation:

Potential energy is energy due to position. It is the product of the object's mass, height, and the gravitational acceleration.

E_p= m \times \ g \times h

The mass of the ball is 3 kilograms and the height is 3 meters. Assuming this is on Earth, the gravitational acceleration is 9.8 meters per square second.

  • m= 3 kg
  • g= 9.8 m/s²
  • h=3 m

Substitute these values into the formula.

E_p= 3 \ kg \times 9.8 \ m/s^2 \times 3 \ m

Multiply the first two numbers.

E_p=29.4 \ kg*m/s^2  \times 3 \ m

Multiply again.

E_p= 88.2 \ kg*m^2/s^2

  • 1 kilogram square meter per square second is equal to 1 Joule.
  • Our answer of 88.2 kg*m²/s² is equal to 88.2 Joules

E_p= 88.2 \ J

The ball has <u>88.2</u> Joules of potential energy.

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A particle of mass 4.00 kg is attached to a spring with a force constant of 100 N/m. It is oscillating on a frictionless, horizo
jeka57 [31]

Answer:

a. A = 0.735 m

b. T = 0.73 s

c. ΔE = 120 J decrease

d. The missing energy has turned into interned energy in the completely inelastic collision

Explanation:

a.

4 kg * 10 m /s + 6 kg * 0 m/s = 10 kg* vmax

vmax = 4.0 m/s

¹/₂ * m * v²max = ¹/₂ * k * A²

m * v² = k * A²  ⇒ 10 kg * 4 m/s = 100 N/m * A²

A = √1.6 m ² = 1.26 m

At = 2.0 m - 1.26 m = 0.735 m

b.

T = 2π * √m / k ⇒ T = 2π * √4.0 kg / 100 N/m = 1.26 s

T = 2π *√ 10 / 100 *s² = 1.99 s

T = 1.99 s -1.26 s = 0.73 s

c.

E = ¹/₂ * m * v²max =

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E₂ = ¹/₂ * 10 * 4² = 80 J

200 J - 80 J  = 120 J decrease

d.

The missing energy has turned into interned energy in the completely inelastic collision

3 0
4 years ago
Which box depicts the tissue level of organization?<br> A) P <br> B) Q <br> C) R <br> D) S
sveta [45]
The right answer is Q).

Explanation:
P) Depicts organ level of organization.
R) Depicts cellular level of organization.
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8 0
3 years ago
A uniform 1.3-kg rod that is 0.67 m long is suspended at rest from the ceiling by two springs, one at each end of the rod. Both
cestrela7 [59]

Answer:

α = 5.75°

Explanation:

In this case, the problem states that both springs have identical lenghts and we also have theri constant. We want to know the angle of the rod with the horizontal. This can be found with the following expression:

sinα = Δx/L

α = sin⁻¹ (Δx/L)    (1)

However, we do not have Δx. This can be found when half of the weight of the rod is balanced. In this way:

F₁ = k₁*x₁   ----> x₁ = F₁ / k₁   (2)

And the force is the weight in half so: F₁ = mg/2

Replacing in (2) we have:

x₁ = (1.3 * 9.8) / (2 * 58) = 0.1098 m

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x₂ = (1.3 * 9.8) / (2 * 36) = 0.1769 m

Now the difference will be Δx:

Δx = 0.1769 - 0.1098 = 0.0671 m

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α = sin⁻¹(0.0671 / 0.67)

<h2>α = 5.75 °</h2>

Hope this helps

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