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sergeinik [125]
3 years ago
15

-s/7-4+3f use s=14 and f=-8 (Last one I swear, I'm sorryxD)

Mathematics
1 answer:
Readme [11.4K]3 years ago
8 0
-s/7-4+3f
Replace s with 14 and f with -8.
-14/7-4+3(-8)
Follow the order of operations: do multiplication and division first, then addition and subtraction.
-2-4-24
Solve:
=-30.
The answer is -30.
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I need to find the steady-state vector.
natta225 [31]
Pls trust me a give me the crown it’s 0.5
5 0
3 years ago
Point b has coordinates (-8,15) and lies on the circle whose equation is x^2+y^2=289. If an angles is drawn in standard position
Alenkinab [10]

Answer:

\cos \theta=-\dfrac{8}{17}

Step-by-step explanation:

Coordinates of Point b=(-8,15)

b lies on the circle whose equation is x^2+y^2=289

x^2+y^2=17^2

Comparing with the general form a circle with center at the origin: x^2+y^2=r^2

The radius of the circle =17 which is the length of the hypotenuse of the terminal ray through point b.

For an angle drawn in standard position through point b,

x=-8 which is negative

y=15 which is positive

Therefore, the angle is in Quadrant II.

\cos \theta=\dfrac{Adjacent}{Hypotenuse} \\$Adjacent=-8\\Hypotenuse=17\\\cos \theta=\dfrac{-8}{17} \\\cos \theta=-\dfrac{8}{17}

8 0
3 years ago
- help help help help help help help help help help
aleksandr82 [10.1K]

Answer:

b = -8

Step-by-step explanation:

6b = -42

Divide by 6 on both sides

b = -8

8 0
3 years ago
Read 2 more answers
Simplify the radical completely.
Sonja [21]

Answer:

D

Step-by-step explanation:

But basically, one by one you try moving the terms out of the radical.

75 is also 25 * 3 and since 25 has a perfect square root of 5 that goes out and 3 stays inside the radical.

x^3 is also x^2 * x and since x^2 has a perfect square root which is just x that goes outside while the remaining x stays inside.

y^9 is also y^8 * y and since we move variables out the radical in twos y^ goes outside the radical and y stays inside alone.

Finally, z is just z it can't be taken out so it stays inside the radical.

Hope that helps!

8 0
3 years ago
If you know the names of the remaining nine students in the spelling​ bee, what is the probability of randomly selecting an orde
rjkz [21]
The probability of getting the correct order in the spelling bee is 1 chance in 362,880.

This is a permutation problem. Our goals is to find the total number of ways that the 9 students can be ordered.

For the first spot there are 9 choices, then 8 choices, then 7 choices....

We need to evaluate:
9 x 8 x 7 x 6 x 5 x 4 x 3 x 2 x 1 = 362,880

Another way to write this is: 9!
8 0
3 years ago
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